Answer:
Explanation:
Given a school bus.
Let say initially the school bus is traveling with speed "v"
Let assume mass of school bus is "m"
Then, the initial kinetic energy is
K.E_initial = ½mv²
Now, if the initial velocity is tripled,
Then, the new velocity is
v_new = 3v.
Note: the mass of the school does not change it is constant
Then, new kinetic energy is
K.E_new = ½m(v_new)²
v_new = 3v
Then,
K.E_new = ½m(3v)²
K.E_new = ½m × 9v²
K.E_new = 9 × ½mv²
Since K.E = ½mv²
Then,
K.E_new = 9 × K.E
So, the new kinetic energy will be 9 times the initial kinetic energy.
So, option D is correct
D. It will be nine times greater.
A. Conductors. Because in conductors, gap between valence band and conduction band is negligible. Due to this electrons from valence band moves spontaneously to conduction band and on small heating the conductors.
Answer:
Protozoa, Algae and Fungus-like protists. And by how they obtain nutrition.
Explanation:
Answer: 1.9 m/s
Explanation:
1) Data:
height, y = 0
range, x = 0.77m
angle, α = 45°
question, horizontal velocity, Vox = ?
2) Physical principles and formulas
Projectile motion.

3) Solution


Factor
![0=t[V_0sin(45)-gt/2]](https://tex.z-dn.net/?f=%200%3Dt%5BV_0sin%2845%29-gt%2F2%5D%20)
Discard t = 0 and solve for the other factor:
![gt/2=V_0sin(45)\\ \\ V_0= gt/(2sin(45))=9.81[0.77/V_{0}cos(45)]/[2sin(45)]\\ \\ V_0^2=9.81[0.77/(2cos(45)sin(45)=9.81[0.77/sin(90)]=7.55\\ \\ V_0}=\sqrt{7.55} =2.8](https://tex.z-dn.net/?f=%20gt%2F2%3DV_0sin%2845%29%5C%5C%20%5C%5C%20%20V_0%3D%20gt%2F%282sin%2845%29%29%3D9.81%5B0.77%2FV_%7B0%7Dcos%2845%29%5D%2F%5B2sin%2845%29%5D%5C%5C%20%5C%5C%20V_0%5E2%3D9.81%5B0.77%2F%282cos%2845%29sin%2845%29%3D9.81%5B0.77%2Fsin%2890%29%5D%3D7.55%5C%5C%20%5C%5C%20V_0%7D%3D%5Csqrt%7B7.55%7D%20%3D2.8%20%20)
Find Vx:
![Vx=V_{0x}=V_{0}cos(45)=2.75(\sqrt{2} /2]=1.9](https://tex.z-dn.net/?f=%20Vx%3DV_%7B0x%7D%3DV_%7B0%7Dcos%2845%29%3D2.75%28%5Csqrt%7B2%7D%20%2F2%5D%3D1.9%20%20)
Vx = 1.9m/s ← answer
Answer: Option C
Magnetic energy | Electromagnetic energy