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Soloha48 [4]
3 years ago
8

Planet C has a tilt of zero degrees. What seasonal changes would be expected on this planet?

Physics
2 answers:
marshall27 [118]3 years ago
8 0
The second statement is your answer:

 No change in temperatures between seasons. Since tilt is the angle between the direction of positive pole and the normal to the orbital plane, seasons occur due to the tilt of axis. If there were to be no, or zero degree tilt, then there will be no season because of the lack in temperature changes. The amount of sunlight received remains same throughout the year which results in no temperature change 

harina [27]3 years ago
4 0
"Tilt of zero degrees" means the planet's rotation axis is "straight up and down".

...  No place on the planet has any seasons.
...  The climate at every place is the same all year around.
...  No place on the planet has any changes in the length of its days.
...  Every place on the planet has 50% light and 50% dark, every day.
...  At the poles, the sun goes around and around and around the horizon. 
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Someone please help me
Schach [20]

Answer:

300x480 teaspoons

Explanation:

when converting cups to teaspoons just multiply by 48

3 0
3 years ago
Read 2 more answers
If you lose control of your vehicle and collide with a fixed object, such as a tree, at 60 m.p.h., the force of impact is the sa
My name is Ann [436]
You can compare the velocity of the car, 60 mph, with the velocity that a mass would acquire when falls from certain height.

First, convert 60 mph to m/s:

60 miles/h * 1.60 km/mile * 1000 m/km * 1h/3600s = 26.67 m/s

Second, calculate from what height a body in free fall reachs 26.67 m/s velocity when hits the floor.

free fall => Vf^2 = 2g*H => H = Vf^2 / (2g)

H = (26.67m/s)^2 / (2*9.8 m/s) = 36.2 m

If you consider that the height between the floors of a building is approximately 3.6 m, you get 36.2 m / 3.6 m/floor = 10 floors.

Then, you conclude that the force of impact is the same as driving you vehicle off a 10 story building.
7 0
4 years ago
A 40-kg rock is dropped from an elevation of 10 m. What is the velocity of the rock when it is 5-m from the ground?
ivolga24 [154]

Answer:

Explanation:

Given

mass of rock m=40\ kg

Elevation of Rock h=10\ m

Distance traveled by rock with time

h=ut+\frac{1}{2}at^2

where, u=initial velocity

t=time

a=acceleration

here initial velocity is zero

when rock is 5 m from ground then it has traveled a distance of 5 m from top because total height is 10 m

5=0\times t+\frac{1}{2}(9.8)(t^2)

t^2=\frac{10}{9.8}

t=1.004\approx 1\ s

velocity at this time

v=u+at

v=0+9.8\times 1.004

v=9.83\ m/s

6 0
4 years ago
If the density of an object is 5.2 g/cm3, and volume is 3.7 cm3, what is its mass
netineya [11]
Here's the equation you use: Density = mass/volume

1) 5.2g/cm^3 = m/3.7cm^3

2) m = 5.2g/cm^3 x 3.7cm^3

3) m = 19.24g

You can check the answer by plugging it in

19.24g/3.7cm^3
= 5.2g/cm^3
6 0
4 years ago
Read 2 more answers
Complete the statement by filling in the Blanks:
Anika [276]

Answer:

induced current

Explanation:

intentionally manipulated.

5 0
3 years ago
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