How are the conditions at which phases are in equilibrium represented on a phase diagram?
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Along the line between liquid and solid, the melting temperatures for different pressures can be found. The junction of the three curves, called the triple point, represents the unique conditions under which all three phases exist in equilibrium together. Phase diagrams are specific for each substance and mixture.
Answer:
The new temperature will be 565.83 K.
Explanation:
Gay Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that the pressure of the gas is directly proportional to its temperature. This means that if the temperature increases, the pressure will increase; or if the temperature decreases, the pressure will decrease.
In other words, Gay-Lussac's law states that when a gas undergoes a constant volume transformation, the ratio of the pressure exerted by the gas temperature remains constant:

When an ideal gas goes from a state 1 to a state 2, it is true:

In this case:
- P1= 180 kPa
- T1= 291 K
- P2= 350 kPa
- T2= ?
Replacing:

Solving:

T2= 565.83 K
<u><em>The new temperature will be 565.83 K.</em></u>
*Go into solution
*Break down
*Liquefy
*Disintegrate
*Melt away
*Evaporate
*Dissapear
Hope it helps! Brainliest answer, PLZ? :)
If x is H+ then <span>x/0.15 = 0.03 and x = 0.0045 M </span><span>and
</span>
<span>Ka = x^2/(0.15 - x) = 0.0045^2/(0.15 - 0.0045) = 1.39 x 10^-4</span>