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DanielleElmas [232]
3 years ago
10

Use the data in the table above to calculate an approximate ΔH∘ in kilojoules for the synthesis of hydrazine from ammonia:

Chemistry
1 answer:
ankoles [38]3 years ago
8 0
DeltaH formation = deltaH of broken bonds - deltaH of formed bonds

Broken bonds: tiple bond N-N and H-H bond
Formed bonds: N-H and N-N bonds

You also have to take note of the molar coefficients

deltaH formation = <span> [(N≡N) + 2 * (H-H)] - [4 * (N-H) + (N-N)] 
                           = (945 + 2*436) - (4*390 + 240)
                            = 17 kJ/mol

The answer is 17 kJ/mol.</span>
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How are the conditions at which phases are in equilibrium represented on a phase diagram?
insens350 [35]

How are the conditions at which phases are in equilibrium represented on a phase diagram?

Image result for How are the conditions at which phases are in equilibrium represented on a phase diagram?

Along the line between liquid and solid, the melting temperatures for different pressures can be found. The junction of the three curves, called the triple point, represents the unique conditions under which all three phases exist in equilibrium together. Phase diagrams are specific for each substance and mixture.

7 0
3 years ago
A 2.5 L container holds a sample of hydrogen gas at 291 K and 180 kPa.
netineya [11]

Answer:

The new temperature will be 565.83 K.

Explanation:

Gay Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that the pressure of the gas is directly proportional to its temperature. This means that if the temperature increases, the pressure will increase; or if the temperature decreases, the pressure will decrease.

In other words, Gay-Lussac's law states that when a gas undergoes a constant volume transformation, the ratio of the pressure exerted by the gas temperature remains constant:

\frac{P}{T} =k

When an ideal gas goes from a state 1 to a state 2, it is true:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 180 kPa
  • T1= 291 K
  • P2= 350 kPa
  • T2= ?

Replacing:

\frac{180 kPa}{291 K} =\frac{350 kPa}{T2}

Solving:

T2=350 kPa*\frac{291 K}{180 kPa}

T2= 565.83 K

<u><em>The new temperature will be 565.83 K.</em></u>

6 0
3 years ago
What are some synonyms for dissolved
Luba_88 [7]
*Go into solution
*Break down
*Liquefy
*Disintegrate
*Melt away
*Evaporate
*Dissapear

Hope it helps! Brainliest answer, PLZ? :)
4 0
4 years ago
A 0.15 m solution of a weak acid is 3.0 dissociated. calculate ka
nalin [4]
If x is H+ then <span>x/0.15 = 0.03 and x = 0.0045 M  </span><span>and
</span>
<span>Ka = x^2/(0.15 - x) = 0.0045^2/(0.15 - 0.0045) = 1.39 x 10^-4</span>
6 0
3 years ago
Read 2 more answers
When 2 or more elements bond together in definite proportions they form a?
Elena L [17]
The answer is compound.
6 0
3 years ago
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