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3 years ago

1. What is the kinetic energy of a frog that has mass of 13kg and can hop 9m/s? *

Physics

1 answer:

emmasim [6.3K]3 years ago

8 0

Answer:526.6J

Explanation:I did a test

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What is the polarization ice cap how long is yes

lubasha [3.4K]

Answer:

What???

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3 years ago

You are working out on a rowing machine. Each time you pull the rowing bar (which simulates the "oars") toward you, it moves a d

tatyana61 [14]

Answer:

54.67 N

Explanation:

The total energy produced is the product of power and time duration:

E = Pt = 82 * 1 = 82 J

Which is converted from work, product of forced extended over a displacement

W = E = Fs = F*1.5 = 82

F = 82 / 1.5 = 54.67 N

So the magnitude of the force exerting on the handle is 54.67 N

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3 years ago

Consider the data collected in science class. Different masses were thrown with varied amounts of

lesya [120]

Answer:

A: In all cases, the acceleration was the same.

Explanation:

I know this because its a clear obvious answer not only that it was one of my USA TESTPREP questions and it was right.

All you mainly have to do is the math - F=ma , In each case , the acceleration is 5 m/s squared

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3 years ago

Read 2 more answers

A dog runs to chase a ball. He travels 6m in 3.2 seconds. How fast is the dog running?

Artyom0805 [142]

So v=d/s so the answer is 6/3.2 so the answer is 1.87m/s

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3 years ago

An 20-cm-long bicycle crank arm, with a pedal at one end, is attached to a 25-cm-diameter sprocket, the toothed disk around whic

Andrej [43]

Answer:

0.033815 m/s²

12.48810875 m

Explanation:

t = Time taken = 12 s

$\omega_f$ = Final angular velocity = 95 rpm

$\omega_i$ = Initial angular velocity = 64 rpm

$\alpha$ = Angular acceleration

$\theta$ = Angle of rotation

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{95\times \frac{2\pi}{60}-64\times \frac{2\pi}{60}}{12}\\\Rightarrow \alpha=0.27052\ rad/s^2$

Tangential acceleration is given by

$a_t=\alpha r\\\Rightarrow a_t=0.27052\times 0.125\\\Rightarrow a_t=0.033815\ m/s^2$

The tangential acceleration of the pedal is 0.033815 m/s²

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{\left(95\times\frac{2\pi }{60}\right)^2-\left(64\times\frac{2\pi}{60}\right)^2}{2\times 0.27052}\\\Rightarrow \theta=99.90487\ rad$

Linear displacement would be $99.90487\times \frac{1}{2\pi}\times 2\pi\times 0.125=12.48810875\ m$

Length of chain that passes in the interval is 12.48810875 m

4 0

3 years ago