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Ainat [17]
3 years ago
7

When 1.95 g of co(no3)2 is dissolved in 0.350 l of 0.220 m koh, what are [ co2+], [ co(oh)42−], and [ oh−] if kf of co(oh)42− =

5.00 × 109?
Chemistry
1 answer:
Airida [17]3 years ago
4 0
Mass of Co(NO₃)₂ = 1.95 g
V KOH = 0.350 L
[KOH] = 0.220 M
Kf = 5.0 x 10⁹
molar mass of Co(NO₃)₂ = 182.943 g/mol
so [Co(NO₃)₂] = 1.95 / (0.350 * 182.943) = 0.03045 M
[Co²⁺] = 0.03045 M
[OH⁻] = 0.22 M
chemical reaction:
             Co²⁺(aq) + 4 OH⁻    ⇄      Co(OH)₄²⁻
I (M)      0.03045      0.22                   0
C (M)   - 0.03045   - 4 (0.03045)      0.03045
E (M)       - x         0.22 - 4(0.03045)   0.03045
                              = 0.0982
Kf  = [Co(OH)₄²⁻] / [Co⁺²][OH⁻]⁴
5.0 x 10⁹ = (0.03045) / x (0.0982)⁴
x = 6.5489 x 10⁻⁸
at equilibrium:
[Co²⁺] = 6.54 x 10⁻⁸
[OH⁻] = 0.0982 M
[Co(OH)₄²⁻] = 0.03045 M



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Reacting bromide (Br₂) with sodium iodine (NaI) will produce sodium bromide (NaBr) and iodine (I₂).

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2 years ago
the temperature of a sample of water increases from 20celsius to 46.6celsius as it absorbs 5650 J of heat. what is the mass of t
Levart [38]

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m = 50.74 kg

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Final temperature of water is 46.6 degrees Celsius

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12. A helium-filled weather balloon has a volume of 2.4 x 102 L at 99 kPa pressure and a
Luba_88 [7]

Answer:

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Explanation:

Data

V = 2.4 x 10² L

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T = 0°C

mass = ?

Process

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P = 99 kPa = 99000 Pa

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                    x       ---------------   99000 Pa

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3.- Substitution

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3 years ago
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