Copper.
Easy to look up, why use brainly? ;P
A bond is formed when electrons are shared between atoms.
<h3>What is the number of unshared pairs?</h3>
A bond is formed when electrons are shared between atoms. This is what we call a shared pair. A lone pair or unshared pair is one that is domiciled on only one of the atoms in the bond.
Let us now look at the molecule shown in image 1;
- The number of unshared pairs in atom a is 0
- The number of unshared pairs in atom b is 2
- The number of unshared pairs in atom c is 0
Let us now look at the molecule shown in image 2;
- The number of unshared pairs in atom a is 1
- The number of unshared pairs in atom b is 2
- The number of unshared pairs in atom c is 3
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Four grams of calcium must be combined with phosphorus to form one mole of the compound Ca3P2
No math is needed to explain this. All that you need to know is that the can (4°C) is in your hand (37°C).
Entropy will always move toward being balanced. Never will you find a lake in which half of it is 1°C and the other half is 70°C; it will be equal throughout.
Remember that "cold" doesn't exist. What we describe to be cold is actually a lack of heat.
So, by applying the two ideas above, it can be concluded that:
Since your hand is warmer than the can, the heat from your hand will be transferred to the can in order to reach an equal temperature.
Answer:
The solutions should be added in this order NaCl > Na2SO4 > Na2S
Explanation:
Silver is insoluble as a chloride, so the silver ions get precipitated on addition of chloride ion as silver chloride. This means Ag+ would be removed the first.
So we will add NaCl in the first step.
The following reaction will occur.
Ag+ + Cl- → AgCl(s)
Both, Pb2 and Ni are soluble as chlorides. (lead chloride is soluble as a hot solution but will ppt when colder).
When we add Na2SO4, Pb2+ will get precipitated (because it's insoluble) as PbSO4 and Ni will remain soluble as NiSO4 is soluble in water.
The reaction that will occur is:
Pb^2+ + SO4^2- → PbSO4(s)
Nickel is insoluble as a sulfide. So when we will add Na2S, nickel will be precipitated as sulfide and be able to separate and be collected.
The solutions should be added in this order NaCl > Na2SO4 > Na2S