Answer:
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Explanation:
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Answer:
1000 m/s
Explanation:
Given that
Mass of the ball, m = 10 g = 0.01 kg
Charge of the ball, q = 2 C
Field strength of the field, E = 5 N/C
Acceleration of the ball, a = ? m/s²
We know the the equation holds,
F = qE, on substituting, we have
F = 2 C * 5 N/C
F = 10 N
Also, we know that
F = ma, and as such,
a = F / m, on substituting we have
a = 10 N / 0.01 kg
a = 1000 m/s²
Therefore, the acceleration of the ball is 1000 m/s²
Answer:
5 x 10⁻⁷N
Explanation:
Given parameters:
Mass of object 1 = 100kg
Mass of object 2 = 300kg
Distance = 2m
Unknown:
Force of gravitational attraction between the objects = ?
Solution:
From Newton's law of universal gravitation we derive an expression:
Fg =
G is the universal gravitation constant = 6.67 x 10⁻¹¹
m is the mass
r is the distance between the bodies
Now insert the parameters and solve;
Fg = 6.67 x 10⁻¹¹ x
= 5 x 10⁻⁷N
corrected question:The heavyweight boxing champion of the world punches a sheet of paper in midair, bringing it from rest up to a speed of 26.5 m/s in 0.044 s . The mass of the paper is 0.003 kg. Part A Find the force of the punch on the paper
Answer:
Force=1.8N
Explanation:
Newtons third law states that in every action there is equal and opposite reaction.
The force of the punch will be the force that moves the paper by a speed of 26.5m/s.


m=0.003kg , v=26.5m/s u=0(the paper is punched from rest) t=0.044s

F=1.8N
Answer:
The acceleration of the refrigerator is 
Explanation:
The expression of the equation of the net force acting on the refrigerator is as follows;
F-f= ma
Here, F is the applied force, f is the force of friction, m is the mass and a is the acceleration.
It is given in the problem that you're having a hard time pushing a refrigerator having mass 355 kg across the kitchen floor. The force of your own push is 993 N. The force of friction opposing your own push is 973 N.
Put F= 993, f= 973 N and m = 355 kg in the above expression of the equation to calculate the acceleration of the refrigerator.
993 - 973 = (355)a
20 = 355 a

Therefore, the acceleration of the refrigerator is
.