1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AveGali [126]
3 years ago
11

You put a new battery into your MP3 player and listen to a song. What are the energy transformations taking place in this system

?

Physics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

B. Chemical energy to electric energy to kinetic energy to sound energy

Explanation:

A battery is a device that converts chemical energy, stored in the chemical substance contained inside the battery, into electric energy, by pushing electrons along the circuit at which the battery is connected.

In an MP3 player, this electron (which form an electric current) pass through a sound transducer, which is a device that converts the electric energy of the current into kinetic energy, by producing the vibrations of the loudspeaker (or of the headphones).

As a result, the air surrounding the loudspeakers/headphones start to vibrate, producing sound waves, and the sound that we hear: in this last stage, therefore, kinetic energy has been converted into sound energy.

You might be interested in
A box with a mass of 2 kg only has four forces acting on it: One force of 16 N due East. One force of 24 N due South. One force
julsineya [31]

Answer:

The magnitude of acceleration is 3 m/s^2.

Explanation:

The net force along North-South direction is 18-24=-6 N.

The net force along East-West direction is 16-16=0 N

The net magnitude of force is square root of (-6)^2+0^2 which is 6 N.

By Newton's Second law,

Force F=ma

Therefore acceleration a=F/m

                                       a=6/2

                                       a=3 m/s^2

Learn more about Newton's second law.

brainly.com/question/13447525

#SPJ10

3 0
2 years ago
Read 2 more answers
A light-rail commuter train blows its 200 Hz horn as it approaches a crossing. The speed of sound is 339 m/s. (a) An observer wa
ddd [48]

Answer:

a) 30.82 m/s

b)  183.33 Hz

Explanation:

a)

V = speed of the sound = 339 m/s

v = speed of the train = ?

f' = observed frequency by the observer = 220 Hz

f = actual frequency of the observer = 200 Hz

using the equation

f' = \frac{fV}{V - v}

220 = \frac{(200)(339)}{339 - v}

v =  30.82 m/s

b)

V = speed of the sound = 339 m/s

v = speed of the train = 30.82 m/s

f'' = observed frequency by the observer as train moves away = ?

f = actual frequency of the observer = 200 Hz

using the equation

f'' = \frac{fV}{V + v}

f'' = \frac{(200)(339)}{339 + 30.82}

f'' = 183.33 Hz

3 0
3 years ago
Help..... disregard my answers...plz help
swat32
What kind of sorcery

6 0
3 years ago
A new interstate highway is being built with a design speed of 120 km/h. For one of the horizontal curves, the radius (measured
nikklg [1K]

Answer:

28.79%

Explanation:

Given

Design Speed, V = 120km/h = 33.33m/s

Radius, R = 300m

Side Friction, Fs = 0.09

Gravitational Constant = 9.8m/s²

Using the following formula, we'll solve the required rate of superelevation.

e + Fs = V²/gR where e = rate

e = V²/gR - Fs

e = (33.33)²/(9.8 * 300) - 0.09

e = 0.287853367346938

e = 28.79%

Hence, the required rate of superelevation for the curve is calculated as 28.79%

4 0
3 years ago
Interactive Solution 6.39 presents a model for solving this problem. A slingshot fires a pebble from the top of a building at a
mariarad [96]

(a) 29.8 m/s

To solve this problem, we start by analyze the vertical motion first. This is a free fall motion, so we can use the following suvat equation:

v_y^2 - u_y^2 = 2as

where, taking upward as positive direction:

v_y is the final vertical velocity

u_y = 0 is the initial vertical velocity (zero because the pebble is launched horizontally)

a=g=-9.8 m/s^2 is the acceleration of gravity

s = -25.0 m is the displacement

Solving for vy,

v_y = \sqrt{u^2+2as}=\sqrt{0+2(-9.8)(-25)}=-22.1 m/s (downward, so we take the negative solution)

The pebble also have a horizontal component of the velocity, which remains constant during the whole motion, so it is

v_x = 20.0 m/s

So, the final speed of the pebble as it strikes the ground is

v=\sqrt{v_x^2+v_y^2}=\sqrt{20.0^2+(-22.1)^2}=29.8 m/s

(b) 29.8 m/s

In this case, the pebble is launched straight up, so its initial vertical velocity is

u_y = 20.0 m/s

So we can find the final vertical velocity using the same suvat equation as before:

v_y^2 - u_y^2 = 2as

v_y = \sqrt{u^2+2as}=\sqrt{(20.0)^2+2(-9.8)(-25)}=-29.8 m/s (downward, so we take the negative solution)

The horizontal speed instead is zero, since the pebble is initially launched vertically, so the final speed is just equal to the magnitude of the vertical velocity:

v = 29.8 m/s

(c) 29.8 m/s

This case is similarly to the previous one: the only difference here is that the pebble is launched straight down instead than up, therefore

u_y = -20.0 m/s

Using again the same suvat equation:

v_y^2 - u_y^2 = 2as

v_y = \sqrt{u^2+2as}=\sqrt{(-20.0)^2+2(-9.8)(-25)}=-29.8 m/s (downward, so we take the negative solution)

As before, the horizontal speed instead is zero, since the pebble is initially launched vertically, so the final speed is just equal to the magnitude of the vertical velocity:

v = 29.8 m/s

We notice that the final value of the speed is always the same in all the three parts, so it does not depend on the direction of launching. This is due to the law of conservation of energy: in fact, the initial mechanical energy of the pebble (kinetic+potential) is the same in all three cases (because the height h does not change, and the speed v does not change either), and the kinetic energy gained during the fall is also the same (since the pebble falls the same distance in all 3 cases), therefore the final speed must also be the same.

7 0
3 years ago
Other questions:
  • Which processes transfer energy from the core to the photosphere
    5·1 answer
  • The efficiency of a Stirling cycle depends on the temperatures of the hot and cold isothermal parts of the cycle.If you increase
    11·1 answer
  • How do I work out this question
    12·1 answer
  • An older-model car accelerates from 0 to speed v in 9.0 s. A newer, more powerful sports car of the same mass accelerates from 0
    13·1 answer
  • Air enters the compressor of a gas-turbine engine at 300 K and 100 kPa, where it is compressed to 700 kPa and 580 K.Heat is tran
    8·1 answer
  • You are in a spaceship moving in a straight line at constant speed. You cannot see out of the ship. Assuming perfectly uniform m
    8·1 answer
  • Please help me I only have a few questions and need this turned in by the end of the day! In all of our simulations we left the
    15·2 answers
  • Can someone proofread this plz? I put my answers next to the number, so all I need you to do is proofread it. the picture for nu
    7·1 answer
  • 1. As the angle of the ramp is increased, the normal force increases /decreases / remains the same and the friction-force increa
    11·1 answer
  • The momentum of the moving depends on which among the given factors?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!