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Gemiola [76]
3 years ago
14

As the distance between two charged objects increases, the strength of the electrical force between the objects

Physics
1 answer:
GuDViN [60]3 years ago
4 0

Answer:

I believe the answer is It increases

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A tool industry characterized by the appearance of hand axes, a bifacial type of blade.
marshall27 [118]
The stone tool industry being described is the Acheulean. These tools are characterized by hand axes and bifacial blades and were made by many different species of Homos, including Homo erectus and early Homo sapiens.
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3 years ago
The basic barometer can be used to measure the height of a building. If the barometric readings at the top and the bottom of a b
erma4kov [3.2K]

Answer:

h = 269.6 m

Explanation:

Pressure at the bottom of the building and at the top of the building must be related as

P_{top} = P_{bottom} - \rho g h

P_{top} = 730 mm Hg

P_{bottom} = 755 mm Hg

now we will have

(755 \times 10^{-3})(13.6 \times 10^3)(9.81) = P_{bottom}

P_{bottom} = 1.007 \times 10^5 Pa

P_{top} = (730\times 10^{-3})(13.6 \times 10^3)(9.81)

P_{top} = 0.974 \times 10^5

now we have

(1.007 - 0.974)\times 10^5 = 1.25 (9.81) h

h = 269.6 m

7 0
3 years ago
How are joules measured ?
saw5 [17]

Answer:You can calculate it by finding the amount of work exerted.

Explanation:

4 0
3 years ago
Read 2 more answers
Two charged particles separated by a distance of = 3 and experienced electrostatic forces of = 60 . What would be this force if
klemol [59]

Answer: 539.4 N

Explanation:

Let's begin by explaining that Coulomb's Law establishes the following:  

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"

What is written above is expressed mathematically as follows:

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}} (1)

Where:

F_{E}=60 N  is the electrostatic force

K=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant  

q_{1} and q_{2} are the electric charges

d=3 m is the separation distance between the charges  

Then:

60 N= 8.99(10)^{9} Nm^{2}/C^{2}\frac{q_{1}.q_{2}}{(3 m)^{2}} (2)

Isolating q_{1} and q_{2}:

q_{1}q_{2}=6(10)^{-8} C^{2} (3)

Now, if we keep the same charges but we decrease the distance to d_{1}=1 m, (1) is rewritten as:

F_{E}=8.99(10)^{9} Nm^{2}/C^{2}\frac{6(10)^{-8} C^{2}}{(1 m)^{2}} (4)

Then, the new electrostatic force will be:

F_{E}= 539.4 N (5) As we can see, the electrostatic force is increased when we decrease the distance between the charges.

4 0
3 years ago
Bones provide both structure and protection for the body. A t. B f
vovikov84 [41]

Answer:

what are you saying man. They do provide structure.

Explanation:

6 0
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