Answer:
v_f = -25.9 m/s
Explanation:
- The complete question is as follows:
" Assume that a pitcher throws a baseball so that it travels in a straight line parallel to the ground. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. Define the direction the pitcher originally throws the ball as the +x direction.
Now assume that the pitcher in Part D throws a 0.145-kg baseball parallel to the ground with a speed of 32 m/s in the +x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. What is the ball's velocity just after leaving the bat if the bat applies an impulse of −8.4N⋅s to the baseball?"
Given:
- mass of baseball m = 0.145 kg
- Speed before impact v_i = 32 m/s
- Speed after impact v_f
- Impulse applied by the bat I = - 8.4Ns
Find:
What is the ball's velocity just after leaving the bat
Solution:
- Impulse is the change in linear momentum of the ball according to Newton's second law of motion:
I = m* ( v_f - v_i )
- Taking the + from pitcher to batsman and - from batsman to pitcher.
- Plug in the values:
-8.4 = 0.145* ( v_f - (32) )
v_f = -57.93103 + 32
v_f = -25.9 m/s
Answer:
one has only one ring and the other has many other lines
Explanation:
the Rutherford Ford model is the one that only has on line and all other atoms are inside
both the more modern one we use has several rings and only two can fit in the very inner rings
Answer:
Detection of x-rays from a binary star undergoing mass exchange, where mass of component star can be determined.
Answer:
415.8N
Explanation:
Given:
weight of a luggage = 69.3 N
But
✓(weight on the Earth) is equivalent to 6 times weight if the moon.
✓Then, weight on the Earth) =( 69.3N × 6)
✓weight on the Earth) = 415.8N
