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Firdavs [7]
2 years ago
8

Find the volume of cuboid of side 4cm. Convert it in SI form​

Physics
1 answer:
MAXImum [283]2 years ago
6 0

Answer:

0.000064 cubic meters.

Explanation:

Given the following data;

Length of side = 4 centimeters

Conversion:

100 centimeters = 1 meters

4 cm = 4/100 = 0.04 meters

To find the volume of cuboid;

Mathematically, the volume of a cuboid is given by the formula;

Volume of cuboid = length * width * height

However, when all the sides are equal the formula is;

Volume of cuboid = L³

Volume of cuboid = 0.04³

Volume of cuboid = 0.000064 cubic meters.

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A car travels 50 kilometers in 30 minutes. Which<br> about the motion of the car are true?
irga5000 [103]

Answer:

1500

Explanation:

is that all the question?

6 0
1 year ago
Give reason Pascal is a derived unit​
Stells [14]

Answer:

Pascal is a derived unit because <u>it</u><u> </u><u>cannot</u><u> </u><u>be</u><u> </u><u>expressed</u><u> </u><u>in</u><u> </u><u>any</u><u> </u><u>physics</u><u> </u><u>terms</u><u>,</u><u> </u><u>but</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>an</u><u> </u><u>expression</u><u> </u><u>of</u><u> </u><u>fundamental</u><u> </u><u>quantities</u><u>.</u>

Explanation:

{ \sf{Pasacal \: ( Pa) =  \frac{newtons}{metres {}^{2} } }} \\  \\ { \sf{Pasacal  \: (Pa) =  \frac{kg \times  {ms}^{ - 2} }{ {m}^{2} } }}

4 0
3 years ago
Calculate the work done by a force of 30 N in lifting a load of 2 kg to a height of 10 m (g = 10 m/s2)
Mars2501 [29]

Answer:

<u>300 J</u>

Explanation:

Given :

  1. Applied force = 30 N
  2. Mass = 2 kg
  3. Height = 10 m
  4. g = 10 m/s²

Work done by the force :

  • Work done = Force x Displacement
  • Work done = mg x h
  • Work done = 30 N x 10 m
  • Work done = <u>300 J</u>

<u></u>

<u><em>Note</em></u> :

  • What you have calculated is the work done by gravitational force on the object (that too, incorrectly)
  • But in the end, it asks for work done by the force of 30N
  • Hence, the given answer ~
3 0
2 years ago
wo plates with area 6.00×10−3 m2 are separated by a distance of 1.50×10−4 m . If a charge of 5.40×10−8 C is moved from one plate
liq [111]

Answer:

V = 152.542 volts

Explanation:

Given data:

area of plates6.00\times 10^{-3} m^2

distance between the plates is 1.50\times 10^{-4} m

charge = 5.40\times 10^{-8} c

we know that capacitance is given as

C = \frac{\epsilon A}{d}

C = \frac{8.85\times 10^{-12} 6\times 10^{-3}}{1.50\times 10^{-4}}

C = 3.54\times 10^{-10} F

potential difference is given as

V =\frac{Q}{C} = \frac{5.40\times 10^{-8}}{3.54\times 10^{-10}}

V = 152.542 volts

3 0
3 years ago
The device or instrument that transforms light energy to electrical energy​
WINSTONCH [101]

Answer:

Solar panels

sun light into electricity

3 0
2 years ago
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