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mina [271]
3 years ago
12

Transparency is a ____ of matter. property substance type

Chemistry
2 answers:
PolarNik [594]3 years ago
8 0

Answer: property i think

Explanation:

Masja [62]3 years ago
3 0

Answer: -property

Explanation: Transparency is a property  of matter.

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It took batman 5 minutes to catch robin in the bat-mobile. If he traveled 45 km before catching him, how fast was he going?
Nataly_w [17]

Answer:

he going zoom zoom

Explanation:

7 0
3 years ago
1. The solubility of lead(II) chloride at some high temperature is 3.1 x 10-2 M. Find the Ksp of PbCl2 at this temperature.
solniwko [45]

Answer:

1) The solubility product of the lead(II) chloride is 1.2\times 10^{-4}.

2) The solubility of the aluminium hydroxide is 1.6\times 10^{-10} M.

3)The given statement is false.

Explanation:

1)

Solubility of lead chloride = S=3.1\times 10^-2M

PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq)

                            S     2S

The solubility product of the lead(II) chloride = K_{sp}

K_{sp}=[Pb^{2+}][Cl^-]^2

K_{sp}=S\times (2S)^2=4S^3=4\times (3.1\times 10^{-2})^3=1.2\times 10^{-4}

The solubility product of the lead(II) chloride is 1.2\times 10^{-4}.

2)

Concentration of aluminium nitrate = 0.000010 M

Concentration of aluminum ion =1\timed 0.000010 M=0.000010 M

Solubility of aluminium hydroxide in aluminum nitrate solution = S

Al(OH)_3(aq)\rightleftharpoons Al^{3+}(aq)+3OH^-(aq)

                            S     3S

The solubility product of the aluminium nitrate = K_{sp}=1.0\times 10^{-33}

K_{sp}=[Al^{3+}][OH^-]^3

1.0\times 10^{-33}=(0.000010+S)\times (3S)^3

S=1.6\times 10^{-10} M

The solubility of the aluminium hydroxide is 1.6\times 10^{-10} M.

3.

Molarity=\frac{Moles}{Volume (L)}

Mass of NaCl= 3.5 mg = 0.0035 g

1 mg = 0.001 g

Moles of NaCl = \frac{0.0035 g}{58.5 g/mol}=6.0\times 10^{-5} mol

Volume of the solution = 0.250 L

[NaCl]=\frac{6.0\times 10^{-5} mol}{0.250 L}=0.00024 M

1 mole of NaCl gives 1 mole of sodium ion and 1 mole of chloride ions.

[Cl^-]=[NaCl]=0.00024 M

Moles of lead (II) nitrate = n

Volume of the solution = 0.250 L

Molarity lead(II) nitrate = 0.12 M

n=0.12 M]\times 0.250 L=0.030 mol

1 mole of lead nitrate gives 1 mole of lead (II) ion and 2 moles of nitrate ions.

[Pb^{2+}]=[Pb(NO_2)_3]=0.030 M

PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq)

Solubility of lead(II) chloride = K_{sp}=1.2\times 10^{-4}

Ionic product of the lead chloride in solution :

Q_i=[Pb^{2+}][Cl^-]^2=0.030 M\times (0.00024 M)^2=1.7\times 10^{-9}

Q_i ( no precipitation)

The given statement is false.

3 0
4 years ago
Identify what kind of ligand (weak or strong), what kind of wavelength (long or short), what kind of spin (high spin or low spin
anzhelika [568]

To find - Identify what kind of ligand (weak or strong), what kind

              of wavelength (long or short), what kind of spin (high spin or

              low spin) and whether it is paramagnetic or diamagnetic for

              the following complexes.

              1. [Mn(CN)6]4-

              2. [Fe(OH)(H2O)5]2

              3. [CrCl4Br2]3-

Step - by - Step Explanation -

1.

[Mn(CN)⁶]⁴⁻ :

Ligand - Strong

Wavelength - Short

Spin - Low spin

Number of unpaired electrons = 1 ∴ paramagnetic.

2.

[Fe(OH)(H₂O)₅]²⁺ :

Ligand - Weak ( both OH⁻ and H₂O )

Wavelength - Long

Spin - High spin

Number of unpaired electrons = 5 ∴ paramagnetic.

3.

[CrCl₄Br₂]³⁻ :

Ligand - Weak ( both Br⁻ and Cl⁻ )

Wavelength - Long

Spin - High spin

Number of unpaired electrons = 3 ∴ paramagnetic.

7 0
3 years ago
Which is true of electric cars?
lianna [129]

Answer:

they produce no DIRECT emissions

Explanation:

that is why they are good in cities to reduce air pollution . but sometypes can produce lesser emissions.

3 0
3 years ago
An iron pipe has a density of 7.86 g/mL and a volume of 324.4 mL. What is the mass of the iron pipe?
wlad13 [49]

Answer:

Mass=2549.784 \ g

Explanation:

The equation for mass is:

Mass = Density * Volume

We plug in the given values into the equation:

Mass = 7.86 \ g/mL * 324.4 \ mL

Mass=2549.784 \ g

6 0
2 years ago
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