What percentage of boys Chose walking

Chemistry

1 answer:

mafiozo [28]2 years ago

6 0

It would of been nice if you were to post your question so others could actually answer it.

You might be interested in

What was the hiker's average velocity during part C of the hike?

umka2103 [35]

Answer:

0.13 km/min west

Explanation:

I just did the test.

6 0

2 years ago

1. What is the colour of FeSO4.7H20 crystals?How does this colour change upon heating? Give balanced

svet-max [94.6K]

1. What is the colour of FeSO4.7H20 crystals?How does this colour change upon heating?

Melanterite or FeSO4.7H20 is green in color
2FeSO4 ---> Fe2O3 + SO2 + SO3

2. a. What are redox reactions?
It is a type of chemical reaction that involves a transfer of electrons between two species.

b.Why is the reaction between MnO2 and HCl a
redox reaction?
Because there are atoms that are reduced and are oxidized.

c.Identify the substance oxidized and the
substance reduced in the above reaction.

MnO2 + 4 HCl ---> MnCl2 + 2H2O + Cl2
Mn was reduced and Cl was oxidized

5 0

2 years ago

Select correct examples of linear molecules for five electron groups. Select correct examples of linear molecules for five elect

Shalnov [3]

Explanation:

Formula to calculate hybridization is as follows.

Hybridization = $\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

So, hybridization of $BeCl_{2}$ is as follows.

Hybridization = $\frac{1}{2}[V + N - C + A]$

= $\frac{1}{2}[2 + 2]$

= 2

Hybridization of $BeCl_{2}$ is sp. Therefore, $BeCl_{2}$ is a linear molecule. There will be only two electron groups through which Be is attached.

Similarly, hybridization of $XeF_{2}$ is calculated as follows.

Hybridization = $\frac{1}{2}[V + N - C + A]$

= $\frac{1}{2}[8 + 2]$

= 5

Therefore, hybridization of $XeF_{2}$ is $sp^{3}d. Therefore, [tex]XeF_{2}$ is also a linear molecule. Though there are three lone pair of electrons present on a xenon atom and it is further attached with fluorine atoms through two electron pairs. Hence, there are in total five electron groups.