Question

determine the concentration of 35.0mL of an acid solution that requires 25.1mL of a 0.50M NaOH to neutralize it

Answer 1

Hello!

The general chemical equation for the neutralization of an acid HA with NaOH is the following:

HA(aq) + NaOH(aq) → NaA(aq) + H₂O(l)

For determining the concentration of the acid solution, we can use the equation shown below:

$moles HA=moles NaOH \\ \\ cHA*VHA=cNaOH*VNaOH \\ \\ cHA= \frac{cNaOH*vNaOH}{VHA}= \frac{0,5M*25,1 mL}{35 mL}=0,36 M$

So, the concentration of the Acid is 0,36 M

Have a nice day!