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Sonbull [250]
3 years ago
12

Write the reaction between Hydrochloric acid and Sodium Hydroxide,

Chemistry
1 answer:
KengaRu [80]3 years ago
8 0
The answer is:

CO2 (g) + H2O ( I) > H2CO3 ( aq) H2CO3 ( aq) + NAOH ( aq) > NaCO3 (aq) + H2O ( I)
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Do diastereomers have different physical properties
ANEK [815]

Answer:

Diastereomers can have different physical properties and reactivity. They have different melting points and boiling points and different densities.

7 0
3 years ago
Choose the term that best describes the following statement: a system in equilibrium will oppose a change in a way that helps re
Scorpion4ik [409]
Le Chatelier's principle (D)
3 0
3 years ago
How many molecules of Acetic Acid (CH3COOH) are in a sample that has a mass of 172.90 g?
STatiana [176]

Answer:

17.46× 10²³ molecules

Explanation:

Given data:

Mass of acetic acid = 172.90 g

Number of molecules = ?

Solution:

First of all we will calculate the number of moles of acetic acid :

Number of moles = mass / molar mass

Number of moles = 172.90 g/ 60.1 g/ol

Number of moles = 2.9 mol

Now the given problem will solve by using Avogadro number.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

2.9 mol × 6.022 × 10²³ molecules  / 1 mol

17.46× 10²³ molecules

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

3 0
3 years ago
When atoms are joined together, they form
Yanka [14]

Answer:

hi

Explanation:

protons,electrons and neutrons form atoms and

atoms form molecules

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5 0
3 years ago
Read 2 more answers
Using the unbalanced reaction below:
Vladimir [108]

1.16 g of UF₄ can be formed in this reaction.

<u>Explanation:</u>

We have to write the balanced equation of the reaction between Uranium oxide and hydrogen fluoride to form Uranium tetra fluoride and water as,

UO₂(s) +4 HF(aq) → UF₄ + 4 H₂O(l)

We can find the moles of UF₄ and then multiplying molar mass of UF₄ with the moles of UF₄, we will get the mass of UF₄ in grams.

Moles of UF₄ =   $  \frac{ 1 mol of UO_{2}\times 1 mol of UO_{2\times 1 mol of UF_{4} }  }{270.03 g \times 1 mol of UO_{2} }

                       = 0.00370 mol UF₄

Grams of UF₄ =0.00370 mol × 314.02 g/mol = 1.16 g of UF₄

So mass of UF₄ formed in the reaction is 1.16 g.

5 0
4 years ago
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