Answer:
O The heat absorbed in Trial 1 is about 3,347) greater than the heat absorbed in Trial 2
Explanation:
Using the formula as follows;
Q = m × c × ∆T
Where;
Q = amount of heat absorbed (J)
m = mass of substance (g)
c = specific heat of water = 4.18J/g°C
∆T = change in temperature (°C)
* For trial 1:
m = 30g
∆T = 40°C - 0°C = 40°C
Q = 30 × 4.18 × 40
Q = 5016J
* For trial 2:
m = 40g
∆T = 40°C - 30°C = 10°C
Q = 40 × 4.18 × 10
Q = 1672J
From the above results, it is clear that the amount of heat absorbed in trial 1 (5016J) is greater than that absorbed in trial 2(1672J) with a difference of 3344.
