Question

Linda performed the following trials in an experiment.

Answer 1

Answer:

O The heat absorbed in Trial 1 is about 3,347) greater than the heat absorbed in Trial 2

Explanation:

Using the formula as follows;

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (J)

m = mass of substance (g)

c = specific heat of water = 4.18J/g°C

∆T = change in temperature (°C)

* For trial 1:

m = 30g

∆T = 40°C - 0°C = 40°C

Q = 30 × 4.18 × 40

Q = 5016J

* For trial 2:

m = 40g

∆T = 40°C - 30°C = 10°C

Q = 40 × 4.18 × 10

Q = 1672J

From the above results, it is clear that the amount of heat absorbed in trial 1 (5016J) is greater than that absorbed in trial 2(1672J) with a difference of 3344.