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Charra [1.4K]
3 years ago
7

Linda performed the following trials in an experiment.

Chemistry
1 answer:
DanielleElmas [232]3 years ago
4 0

Answer:

O The heat absorbed in Trial 1 is about 3,347) greater than the heat absorbed in Trial 2

Explanation:

Using the formula as follows;

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (J)

m = mass of substance (g)

c = specific heat of water = 4.18J/g°C

∆T = change in temperature (°C)

* For trial 1:

m = 30g

∆T = 40°C - 0°C = 40°C

Q = 30 × 4.18 × 40

Q = 5016J

* For trial 2:

m = 40g

∆T = 40°C - 30°C = 10°C

Q = 40 × 4.18 × 10

Q = 1672J

From the above results, it is clear that the amount of heat absorbed in trial 1 (5016J) is greater than that absorbed in trial 2(1672J) with a difference of 3344.

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Construct a simulated proton-decoupled 13C NMR spectrum for tert-butyl alcohol. Drag the resonance signal icon to the appropriat
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Answer:

                     The ¹³C-NMR Spectrum of  <em>tert</em>-butyl alcohol will show only two signals.

(i) Signal at around 31 ppm:

                                              This signal towards upfield is for the carbon atoms which are more shielded and are having rich electron surroundings. The height of peak at y-axis shows the number of carbon atoms as compared to other peaks. In this case it is three times the height of second signal hence, it shows that this peak corresponds to three carbon atoms.

(ii) Signal at around 70 ppm:

                                              This signal towards downfield is for the carbon atom which is more deshielded and is having electron deficient surrounding. As compared to the second signal the height of this peaks corresponds to only one carbon. And the deshielded environment shows that this carbon is directly attached to an electronegative element.

4 0
4 years ago
How much energy (heat) is required to convert 248 g of water from 0 oC to 154 oC? Assume that the water begins as a liquid, that
Nuetrik [128]

Answer:

The total heat required is 691,026.36 J

Explanation:

Latent heat is the amount of heat that a body receives or gives to produce a phase change. It is calculated as: Q = m. L

Where Q: amount of heat, m: mass and L: latent heat

On the other hand, sensible heat is the amount of heat that a body can receive or give up due to a change in temperature. Its calculation is through the expression:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the change in temperature (Tfinal - Tinitial).

In this case, the total heat required is calculated as:

  • Q  for liquid water.  This is, raise 248 g of liquid water from O to 100 Celsius. So you calculate the sensible heat of water from temperature 0 °C to 100° C

Q= c*m*ΔT

Q=4.184\frac{J}{g*C} *248 g* (100 -0 )C

Q=103,763.2 J

  • Q  for phase change from liquid to steam. For this, you calculate the latent heat with the heat of vaporization being 40 and being 248 g = 13.78 moles (the molar mass of water being 18 g / mol, then\frac{248 g}{18 \frac{g}{mol} } =13.78 moles )

Q= m*L

Q=13.78moles*40.79 \frac{kJ}{mol}

Q=562.0862 kJ= 562,086.2 J (being 1 kJ=1,000 J)

  • Q for temperature change from  100.0 ∘ C  to  154 ∘ C, this is, the sensible heat of steam from 100 °C to 154°C.

Q= c*m*ΔT

Q=1.99\frac{J}{g*C} *248 g* (154 - 100 )C

Q=25,176.96 J

So, total heat= 103,763.2 J + 562,086.2 J + 25,176.96 J= 691,026.36 J

<u><em>The total heat required is 691,026.36 J</em></u>

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What is potential energy?
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Answer:

B

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