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aalyn [17]
3 years ago
11

Which number should be placed before H20 on the products side of the equation to

Chemistry
1 answer:
timama [110]3 years ago
8 0
<h2>The required balanced equation:</h2><h2>C_3H_8 +5O_2 = 3CO_2 + 4H_2O</h2>

Explanation:

•  Propane when reacts with oxygen it gives carbon dioxide and water.

  • In order to make the equation balanced at both ends of the equation,  

Add 4 as a coefficient before on L.H.S (Left Hand Side) of Equation.

• Therefore, the required balanced equation is:

Propane, when added with 5 molecules of Water, yields 3 molecules of Carbon Dioxide and 4 molecules of water, as shown in the below equation -

C_3H_8 +5O_2 = 3CO_2 + 4H_2O

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How to tell the difference between ionic and covalent bonding?
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4 0
3 years ago
A 35.0-mL solution of 0.075 M CaCl2 is mixed with 25.0 mL of 0.090 M BaCl2.
Korolek [52]

Answer:

The fluoride which precipitates first is CaF₂

Explanation:

When F⁻ is added, CaF₂ and BaF₂ are produced following the ksp equation:

For CaF₂:

Ksp = 3.2x10⁻¹¹ = [Ca²⁺] [F⁻]²

<em>Where [Ca²⁺] = 0.075M * {35mL / (25mL + 35mL)} = 0.04375M</em>

3.2x10⁻¹¹ = [0.04375M] [F⁻]²

[F⁻]² = 7.31x10⁻¹⁰

[F⁻] = 2.7x10⁻⁵M

<h3>CaF₂ begins precipitation when [F⁻] = 2.7x10⁻⁵M.</h3>

For BaF₂:

Ksp = 1.5x10⁻⁶ = [Ba²⁺] [F⁻]²

<em>Where [Ba²⁺] = 0.090M * {25mL / (25mL + 35mL)} = 0.0375M</em>

1.5x10⁻⁶ = [0.0375M] [F⁻]²

[F⁻]² = 4x10⁻⁵

[F⁻] = 6.3x10⁻³M

BaF₂ begins precipitation when [F⁻] = 6.3x10⁻³M

Thus, the fluoride which precipitates first is CaF₂

4 0
3 years ago
For a single substance at atmospheric pressure, classify the following as describing a spontaneous process, a nonspontaneous pro
Maslowich

Answer and Explanation:

a. Solid melting below its melting point  ⇒ Nonspontaneous

The process is spontaneous <u>above</u> the melting point.

b. Gas condensing below its condensation point  ⇒ Spontaneous

Below the condensation point, the subtance is liquid (it condenses)

c. Liquid vaporizing above its boiling point  ⇒ Spontaneous

A liquid vaporizes at a temperature above the boiling point, it passes from liquido to the gas state

d. Liquid freezing below its freezing point  ⇒ Spontaneous

A liquid freezes at a temperature below its freezeing point, it passes from the liquid to the solid state.

e. Liquid freezing above its freezing point  ⇒ Nonspontaneous

The freezing is spontaneous below the freezing point.

f. Solid melting above its melting point  ⇒ Spontaneous

A solid melts at a temperature above the melting point

g. Liquid and gas together at boiling point with no net condensation or vaporization  ⇒ Equilibrium system

The systems is at equilibrium: there is no net change toward the liquid or towards the gas state.

h. Gas condensing above its condensation point  ⇒ Nonspontaneous

The condensation is spontaneous at a temperature below the condensation point.

i. Solid and liquid together at the melting point with no net freezing or melting ⇒ Equilibrium system

The system is at equilibrium: there is no net change towards the solid or the liquid state.

5 0
3 years ago
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