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Otrada [13]
3 years ago
6

In a cup of liquid water when would water molcules stop moving

Physics
2 answers:
Igoryamba3 years ago
6 0
Never. Molecules never stop moving; they only slow or speed up. They will only stop at absolute 0, which is impossible to get to,
Mandarinka [93]3 years ago
3 0
The the Water turns to ice. But even then they would never truly stop moving.<span />
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find the mass of a ball on a roof 30 meters high, if the ball's gravitational potential energy is 58.8 joules
Sidana [21]
We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.
3 0
3 years ago
Read 2 more answers
A 225-g object is attached to a spring that has a force constant of 74.5 N/m. The object is pulled 6.25 cm to the right of equil
snow_lady [41]

Answer:

1.137278672 m/s

+5.9 cm or -5.9 cm

Explanation:

A = Amplitude = 6.25 cm

m = Mass of object = 225 g

k = Spring constant = 74.5 N/m

Maximum speed is given by

v_m=A\omega\\\Rightarrow v_m=A\sqrt{\dfrac{k}{m}}\\\Rightarrow v_m=6.25\times 10^{-2}\times \sqrt{\dfrac{74.5}{0.225}}\\\Rightarrow v_m=1.137278672\ m/s

The maximum speed of the object is 1.137278672 m/s

Velocity is at any instant is given by

\dfrac{v_m}{3}=\omega\sqrt{A^2-x^2}\\\Rightarrow \dfrac{A\omega}{3}=\omega\sqrt{A^2-x^2}\\\Rightarrow \dfrac{A}{3}=\sqrt{A^2-x^2}\\\Rightarrow \dfrac{A^2}{9}=A^2-x^2\\\Rightarrow A^2-\dfrac{A^2}{9}=x^2\\\Rightarrow x^2=\dfrac{8}{9}A^2\\\Rightarrow x=A\sqrt{\dfrac{8}{9}}\\\Rightarrow x=6.25\times 10^{-2}\sqrt{\dfrac{8}{9}}\\\Rightarrow x=\pm 0.0589255650989\ m

The locations are +5.9 cm or -5.9 cm

4 0
3 years ago
Need help answering this question for #30
dezoksy [38]
I think u would add them all up and then write down your answers
6 0
3 years ago
Read 2 more answers
The Canadian bobsled team hit the brakes on the sled they are traveling East in so that it decelerates at a rate of 0.43
mafiozo [28]

Answer:

Explanation:

85 = ½(0.43)t²

t = √(2(85)/0.43)

t = 19.883380...

t = 20 s

v→ 8.55 m/s initial, 0 m/s final

a← 0.43 m/s²

8 0
2 years ago
As the space shuttle orbits the Earth, the shuttle and the astronauts
maxonik [38]

Answer:

a=g.  

the body is in one of these INGRAVIDITY, so the weight of the body would be ZERO

Explanation:

When the spacecraft revolves around the Earth, it is subjected to Newton's second law

          F = m a

where the force is the universal attractive force, the mass of the astronauts, and the centripetal acceleration.

         a = F / m

         a = (G M m / r²) / m

         a = G M / r²

the amount of is the acceleration of gravity at height r.

         a = g

Therefore, we see that the acceleration of the body is equal to the acceleration of gravity, which is why the body is in one of these INGRAVIDITY, so the weight of the body would be ZERO

3 0
3 years ago
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