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Leokris [45]
2 years ago
10

Find the relationship between 'g' and 'G'​

Physics
2 answers:
Paha777 [63]2 years ago
6 0
G is the gravitational acceleration while G is the gravitational constant. Both variables are related by the equation g = GM/r^2 where M is mass of an object and r is the distance from the centre of the object.
mel-nik [20]2 years ago
4 0
Lower case and upper case
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All matter is made up of subatomic particles that contain atoms.TrueFalse
antiseptic1488 [7]

All matter is made up of subatomic particles that contain atoms. This is false statement.

Everything in the universe  is made of matter, and so, everything in the universe is made of atoms. An atom itself is made up of three tiny kinds of particles called subatomic particles: <u>protons, neutrons, and electrons</u>.

All matter is made up of substances called elements, which have specific chemical and physical properties and cannot be broken down into other substances through ordinary chemical reactions.

Matter is anything which have mass and occupy some volume.

On earth, solid, liquid, and gas are the most common states of matter. Not only is water the most common substance on earth, but it is also the only substance that commonly appears as a solid, a liquid, and a gas within the normal range of earth's temperatures.

Learn more about matter here:- brainly.com/question/16982523

#SPJ9

3 0
1 year ago
A 50.0 Watt stereo emits sound waves isotropically at a wavelength of 0.700 meters. This stereo is stationary, but a person in a
photoshop1234 [79]

Answer:

a) f' = 432 Hz

b) I = 8.12*10^-4 W/m^2

Explanation:

a) To calculate the frequency of sound waves that car receives, you take into account the Doppler effect. In this case (observer moves away of the source) you have the following formula:

f'=f(\frac{v-v_o}{v+v_s})    (1)

where

f: frequency of the source = ?

v: speed of sound = 343 m/s

vo: speed of the observer = 40.0 m/s

vs: speed of the source = 0 m/s (stationary)

You replace the values of all parameters in the equation (1):

To calculate f' you first calculate the frequency of the sound wave, by using the following formula:

v=\lambda f\\\\

v: speed of sound

λ: wavelength = 0.700 m

f=\frac{v}{\lambda}=\frac{343m/s}{0.700m}=480Hz

Next, you replace the values of all parameters in the equation (1):

f'=(490Hz)(\frac{343m/s-40.0m/s}{343m/s})=432Hz

hence, the frequency perceived by the car is 432 Hz

b) To calculate the power of the sound wave, when the car is 70.0 maway from the speaker, you use the following formula:

I=\frac{P}{4\pi r^2}

P: power of the source = 50.0 W

r: distance to the source = 70.0 m

I=\frac{50.0 W}{4\pi(70.0m)^2}=8.12*10^{-4}\frac{W}{m^2}

hence, the intensity is 8.12*10^⁻4 W/m^2

3 0
3 years ago
1. A piece of metal weighs 50.0 N in air, 36.0 N in water, and 41.0 N in an unknown
denis23 [38]

Answer:

a) 3.37 x 10^{3} kg/m^3

b) 6.42kg/m^{3}

Explanation:

a) Firstly we would calculate the volume of the metal using it`s weight in air and water , after finding the weight we would find the density .

Weight of metal in air = 50N = mg implies the mass of metal is 5kg.

Now the difference of weight of the metal in air and water = upthrust acting on it = volume (metal) p (liquid) g = V (1000)(10) = 14N. So volume of metal piece = 14 x 10^{-4}  kg/m^{3}. So density of metal = mass of metal / volume of metal = 5 / 14 x 10^{-4}  kg/m^{3} = 3.37 x 10^{3} kg/m^3

b) Water exerts a buoyant force to the metal which is 50−36 = 14N, which equals the weight of water displaced. The mass of water displaced is 14/10 = 1.4kg Since the density of water is 1kg/L, the volume displaced is 1.4L. Hence, we end up with 3.57kg/l. Moreover, the unknown liquid exerts a buoyant force of 9N. So the density of this liquid is 6.42kg/m^{3}

3 0
3 years ago
2. Different kinds of light are produced from waves of different ____________________.
gregori [183]

Answer: Either electromagnetic radiation or energy is the answer to your question.

4 0
3 years ago
Describe the phases of the moon along with a picture.​
Alex787 [66]

Answer:

The eight Moon phases:

Waxing Crescent: In the Northern Hemisphere, we see the waxing crescent phase as a thin crescent of light on the right. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon.

The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.

<h2>The 8 phases (in order) are:</h2>
  • New moon.
  • Waxing Crescent.
  • First Quarter.
  • Waxing Gibbous.
  • Full moon.
  • Waning Gibbous.
  • Third Quarter.
  • Waning Crescent.

Explanation:

Hope it is helpful....

5 0
3 years ago
Read 2 more answers
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