From Kepler's 3rd law, time period of satellite orbiting around planet in a circular orbit is given by,
T² = 4π²r³/GM
M= mass of the Earth = 6×10²⁴ Kg.
∴ T² = 4×3.14²×(2.56×10⁷)³/6.67×10⁻¹¹×6×10²⁴
T² = 1653339719
∴ T = 40661.28 seconds.
Answer:
B. The two sleds will move to the right.
Explanation:
I majored in physics
The force between the molecules involved in the bond is 6. 426 *10^-11 Newton
<h3>How to determine the force</h3>
Using the formula:
F = K[q1 x q2]/D^2
where K is coulombs constant =9 *10 ^9 Nm^2/C^2.
q1 and q2 = charges = 1.60x10 -20C
d = distance between the charges = 2x10 -10 m
Substitute the values into the formula
F =
F =
F =
F = Newton
Thus, the force between the molecules involved in the bond is 6. 426 *10^-11 Newton
Learn more about electrostatic force here:
brainly.com/question/8424563
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Work = (force) x (distance)
When a force of 150 N pushes through a distance of 13 meters,
it does
Work = (150 N) x (13 m) = 1,950 joules .