Answer:
(a) Angular acceleration is 1.112 rad/s².
(b) Average angular velocity is 2.78 rad/s .
Explanation:
The equation of motion in Rotational kinematics is:
θ = θ₀ + 0.5αt²
Here θ is angular displacement at time t, θ₀ is angular displacement at time t=0, t is time and α is constant angular acceleration.
(a) According to the problem, θ is 13.9 rad, θ₀ is zero as it is at rest and t is 5 s. Put these values in the above equation:
13.9 = 0 + 0.5α(5)²
α = 1.112 rad/s²
(b) The equation of average angular velocity is:
ω = Δθ/Δt
ω = 
ω = 2.78 rad/s
Answer:
The correct answer to that question is HENRY
Answer:
Is this for zoommmmmmmmmm?
Explanation:
It had to be 20 letters I had to do something
The equation relates energy to mass
Since the acceleration is uniform, we can calculate it from the data we are given:
a = (vf - vi)/2
where vf=33 m/s and vi=11 m/s
Then use Suvat's equation:
x(t) = vi*t + 0.5 * a * t
where t=20s