Answer:
Wy = - 268.3*cos(42) = - 199.38 [N]
Wx = 268.3*sin(42) = 179.52 [N]
Explanation:
To solve this problem we must make a free body diagram, in the attached image we can see a free body diagram.
Taking the inclined X & y axes with the same angle of 42°, we can see that the weight can be decomposed on both axes.
Since the angle is adjacent to the y-axis, we can use the cosine function
Wy = - 268.3*cos(42) = - 199.38 [N]
Wx = 268.3*sin(42) = 179.52 [N]
Answer:
Explanation:
a Downward acceleration of car A along the slope
= g sinθ - μ g cosθ
= g ( sinθ - μ cosθ)
= 9.8 ( sin 12 - .6 x cos 12 )
= 9.8 x ( .2079 - .5869 )
= - 3.714 m / s²
So there will be deceleration
v² = u² - 2 a s
= 18² - 2 x 3.714 x 24
= 324 - 178
= 146
v = 12 .08 m /s
b )
In the second case , kinetic friction changes
downward acceleration
= g ( sinθ - μ cosθ)
= 9.8 ( sin12 - .1 x cos 12 )
9.8 ( .2079 - .0978 )
= 1.079 m /s
there will be reduced acceleration
v² = u² - 2 a s
= 18² +2 x1.079 x 24
= 324 + 52
= 376
v = 19.4 m /s
Answer:
Explanation:
Given
Weight of helicopter 
inclination of blades with vertical 
Suppose
is the lifting Force
Now using F-B-D
as helicopter is moving with constant velocity
balancing forces in Vertical Force





Now sin component of lift is air resistance

where R=air resistance


