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Lady bird [3.3K]
4 years ago
10

A provider order states, “meperidine (demerol®) 45 mg, atropine sulfate (atropine®) 0.3 mg im now.” the meperidine (demerol®) co

mes in a pre-filled syringe containing 50 mg/ml, and the atropine sulfate (atropine®) comes in a vial containing 400 mcg/ml. what is the total volume that the nurse will be injecting?
Chemistry
1 answer:
alexandr402 [8]4 years ago
4 0
To find the volume, just divide the mass by the dosage in mass per volume. Then, add both volumes to find the total volume. The solution is as follows:

45 mg ÷ 50 mg/mL = 0.9 mL

For the second unit, mcg is micrograms. For every 1 mcg, there is 0.001 mg. Thus,

400 mcg/ml * 0.001 mg/1 mcg = 0.4 mg/mL
0.3 mg ÷ 0.4 mg/mL = 0.75  mL

Total Volume = 0.9 mL + 0. 75 mL = 1.65 mL
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What is the molarity of a solution that contains 4.3 mol of acetic acid (C2H3O2) in 450. mL of solution?
lord [1]

Hey there !


Number of moles of solution: 4.3 moles

Volume in liters:

450.0 mL / 1000 => 0.45 L

Therefore:

Molarity = number of moles / volume of solution ( L)

Molarity = 4.3 / 0.45

=> 9.55 M

Hope that helps!

3 0
3 years ago
What are the safety procedures for nuclear accidents nowadays?
Zigmanuir [339]

Explanation:

Take shelter in a hard wall building

Close doors and windows cut off ventilation

4 0
3 years ago
Hydrogen iodide is not produced by the same method is for hydrogen chloride why with reaction​
Masja [62]

Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...

Using an ionic chloride and Phosphoric acid

H3PO4 + NaCl ==> HCl + NaH2PO4

H3PO4 + NaI ==> HI + NaH2PO4

H2SO4 + NaCl ==> HCl + NaHSO4

This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.

The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.

2I-² === I2 + 2e-

5 0
3 years ago
A large container holds 2 liters of water. 45.0 grams of NaCl is added to the container. What is the molarity of sodium chloride
djverab [1.8K]

Answer:

THE MOLARITY OF SODIUM CHLORIDE IN THE CONTAINER IS 0.3846 M.

Explanation:

Molarity of a solution is the number of moles of solute per dm3  of solution.

Mass concentration = Molar concentration * Molar mass

1. calculate the mass concentration;

Mass conc. = 45 g in 2 L

= 45 g in 2 dm3

In 1 dm3, the mass will be 45 / 2

= 22.5 g/dm3 of NaCl.

2. Calculate the molar mass;

(Na = 23, Cl = 35.5)

Molar mass = ( 23 + 35.5 ) g/mol

Molar mass = 58.5 g/mol

3. calculate the molarity

Molarity = mss concentration / molar mass

Molarity = 22.5 g/dm3 / 58.5 g/mol

Molarity = 0.3846 mol/dm3 of NaCl.

The molarity of sodium chloride in the container is 0.3846 mol/dm3

4 0
3 years ago
Which of the following does not describe a solid
Liono4ka [1.6K]

Answer:

water is not a solid and a rock is a solid

4 0
3 years ago
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