<h3>Answer:</h3>
Volume = 11.2 L
<h3>Explanation:</h3>
Step 1: Calculate Moles:
As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.
The relation between Moles, Number of Particles and Avogadro's Number is given as,
Number of Moles = Number of Particles ÷ 6.022 × 10²³
Putting values,
Number of Moles = 3.01× 10²³ Particles ÷ 6.022 × 10²³
Number of Moles = 0.50 Moles
Step 2: Calculate Volume:
As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.
When 1 mole gas occupies 22.4 dm³ at STP then the volume occupied by 0.50 moles of gas is calculated as,
= (22.4 dm³ × 0.50 moles) ÷ 1 mole
= 11.2 dm³ ∴ 1dm³ = 1 L
So,
Volume = 11.2 L
The answer is N - N.
Purely covalent bond is formed by sharing electrons of atoms with same electronegativity to meet the octet rule (2 or 8 electrons in the valence shell).
Ne is a noble gas and has already 8 electrons in the valence shell, so it will not form a Ne - Ne bond.
Na is an alkaly metal with 1 electron in the valence shell and it does not form a true ionic bond but what is known a metallic bond.
N is a gas that forms a diatomic molecule N - N by sharing the valence electrons in a purely covalent bond.
Ni - O is a metal - non metal compound so it has a ionic character.
Answer:
The student did not lose any organic product in the aqueous layer
Explanation:
From the question;
After addition of hydrochloric acid, a student removes the lower aqueous layer and extracts the aqueous phase with diethyl ether (0.5 mL).
The only possible way the student could have lose the product was if there are some basic group e.g 
in the compound which have a tendency of forming 
salt.
Also these compound could be regenerated from aqueous layer by neutralizing the aqueous layer with basic solution , for example; by using sodium hydroxide (NaOH) in which the extraction is then followed by the usage of Diethyl ether.
Answer:
824 g
Explanation:
First we <u>convert 7.0 x 10²⁴ formula units of magnesium chloride (MgCl₂) into moles</u>, using <em>Avogadro's number</em>:
- 7.0 x 10²⁴ formula units ÷ 6.023x10²³ formula units/mol = 11.62 mol MgCl₂
There are two Cl moles per MgCl₂ moles, meaning that we have (2 * 11.62) 23.24 moles of Cl
Finally we <u>convert 23.24 moles of chlorine into grams</u>, using <em>chlorine's molar mass</em>:
- 23.24 mol * 35.45 g/mol = 824 g
