Answer:
λ = 0.45×10⁻⁶ m
Explanation:
Given data:
Wavelength of blue light = ?
Frequency of blue light = 6.69×10¹⁴ s⁻¹
Solution:
Formula;
Speed of wave = wavelength × frequency
Speed of wave = 3.00×10⁸ m/s
by putting vales,
3.00×10⁸ m/s = λ × 6.69×10¹⁴ s⁻¹
λ = 3.00×10⁸ m/s / 6.69×10¹⁴ s⁻¹
λ = 0.45×10⁻⁶ m
125 Each half life it divides by 2 the amount
1000/2=500
500/2=250
250/2=125
Answer:
The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg
Explanation:
Heat gain by ice = Heat lost by water
Thus,
Heat of fusion + 
Where, negative sign signifies heat loss
Or,
Heat of fusion + 
Heat of fusion = 334 J/g
Heat of fusion of ice with mass x = 334x J/g
For ice:
Mass = x g
Initial temperature = 0 °C
Final temperature = 6 °C
Specific heat of ice = 1.996 J/g°C
For water:
Volume = 353 mL
Density of water = 1.0 g/mL
So, mass of water = 353 g
Initial temperature = 26 °C
Final temperature = 6 °C
Specific heat of water = 4.186 J/g°C
So,


345.976x = 29553.16
x = 85.4197 kg
Thus,
<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>
Answer:
The answer to your question is It will be formed 0.39 moles of H₂
Explanation:
Data
moles of H₂ = ?
moles of HCl = 0.78
moles of Zinc = excess
Balanced chemical reaction
2 HCl + Zn ⇒ 1 H₂ + ZnCl₂
Process
1.- Use proportions to solve this problem. Consider the coefficients of the balanced reaction.
2 moles of HCl ---------------------- 1 mol of H₂
0.78 moles of HCl ----------------- x
x = (0.78 x 1) / 2
- Simplification
x = 0.78 / 2
- Result
x = 0.39 moles of H₂