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svet-max [94.6K]
3 years ago
5

Room temperature is often assumed to be 25∘c. Calculate the molar volume of an ideal gas at 25∘c and 1 atm pressure.

Chemistry
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

  • 24.5 liter / mol

Explanation:

<u>1) Data:</u>

a) T = 25°C = 25 + 273.15K = 298.15 K

b) P = 1 atm

c) assumption: ideal gas

<u>2) Formulae and principles</u>

a) Ideal gas equation: p V = n R T, where:

  • p = pressure
  • V = volume
  • n = number of moles
  • R = universal constant of gases = 0.0821 atm-liter / K-mol
  • T = absolute temperature (Kelvin)

b) Molar volume: ν = V / n, where:

  • ν = molar volume
  • V = volume
  • n = number of moles

<u>3)  Solution:</u>

  • p V = n R T⇒ V/n = ν = RT / p =

                                            = 0.0821 atm-liter / mol-K × 298.15 K / 1 atm

                                            = 24.5 liter / mol                           

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2 Ag+ + 2 e- --> 2 Ag

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In a single displacement reaction between sodium phosphate and barium, how much of each product (in grams) will be formed from 1
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Next, we shall determine the mass of Ba that reacted and the mass of Na and Ba3(PO4)2 produced from the equation.

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Summary:

From the balanced equation above,

411g of Ba reacted to produce 138g of Na and 601g of Ba3(PO4)2.

A. Determination of the mass of Na produced by reacting 10g of Ba.

From the balanced equation above,

411g of Ba reacted to produce 138g of Na.

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From the balanced equation above,

411g of Ba reacted to produce 601g of Ba3(PO4)2.

Therefore, 10g of Ba will react to produce = (10 x 601)/411 = 14.62g of Ba3(PO4)2.

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