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Minchanka [31]
3 years ago
13

As described by the free-radical theory, exposure to oxidizing agents results in unstable oxygen compounds that can be neutraliz

ed by antioxidants. What antioxidant does the body produce?
Chemistry
1 answer:
AnnyKZ [126]3 years ago
4 0

Answer: The body produce NADPH a reducing equivalents as antioxidants.

Explanation:

During the pentose phosphate pathway reducing equivalents like NADPH is produced which help to prevent oxidative stress. It reduces glutathione via glutathione reductase which converts reactive H2O2 to H2O by glutathione peroxidase.

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IgorLugansk [536]

Answer:

1024 sodium atoms.

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Grasshopper population will increase since they have less predators
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2 years ago
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2. Classify the following solutions as acidic, basic, or neutral at 25OC.
PilotLPTM [1.2K]

Answer: a) pH = 13.00 : basic

b) [H_3O^+]=1.0\times 10^{-12}: basic

c) pOH = 5.00 : basic

d) [OH^-]=1.0\times 10^{-9}: acidic

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H_3O^+]

Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.

a) pH = 13.00

As pH is more than 7, the solution is basic.

b)  [H_3O^+]=1.0\times 10^{-12}

Putting in the values:

pH=-\log[1.0\times 10^{-12}]

pH=12

As pH is more than 7, the solution is basic.

c) pOH = 5.00

pH+pOH=14.0

pH=14.0-5.00=9.00

As pH is more than 7, the solution is basic.

d) [OH^-]=1.0\times 10^{-9}

Putting in the values:

pOH=-\log[1.0\times 10^{-9}]

pOH=9.00

pH+pOH=14.0

pH=14.0-9.00=5.00

As pH is less than 7, the solution is acidic.

3 0
3 years ago
Which organelles surround the cell?
GalinKa [24]

Answer:

Cell Wall, Cell Membrane, Nucleus, Endoplasmic Reticulum (ER), and Ribosome.

Explanation:

Hopefully this helps :).

5 0
3 years ago
Read 2 more answers
A 34.53 ml sample of a solution of sulfuric acid, h2s04, reacts with 27.86 ml of 0.08964 m naoh solution. calculate the molarity
Gnoma [55]
The balanced equation between NaOH and H₂SO₄ is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of moles of NaOH moles reacted = molarity of NaOH x volume
number of NaOH moles = 0.08964 mol/L x 27.86 x 10⁻³ L = 2.497 x 10⁻³ mol
according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
number of moles of H₂SO₄ reacted - 1.249 x 10⁻³ mol 
Number of H₂SO₄ moles in 34.53 mL - 1.249 x 10⁻³ mol 
number of H₂SO₄ moles in 1000 mL - 1.249 x 10⁻³ mol / 34.53 x 10⁻³ L = 0.03617 mol 
molarity of H₂SO₄ is 0.03617 M
6 0
3 years ago
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