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iogann1982 [59]
3 years ago
5

Which of the following requires an oxidizing agent?

Chemistry
1 answer:
Wittaler [7]3 years ago
4 0
Ag+ yields Ag is the answer. <span>An </span>oxidizing agent<span>, or oxidant, gains electrons and is reduced in a chemical reaction and it is  also known as the electron acceptor.</span>
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The distance between two corresponding parts of a wave is the wave's
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That would be the e
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Where do humans get nitrogen from?
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All humans get nitrogen from the atmosphere
Nitrogen is available in abundance
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3 years ago
Kim Chemist proposes that increasing the proportion of butadiene in her glue formulation will make the glue stickier. Her propos
Sunny_sXe [5.5K]

Answer: option D) hypothesis

Explanation:

Kim proposal is an hypothesis, because it is an assumption that will ONLY be accepted as true (i.e becomes a theory) when butadiene successfully makes the glue stickier in several conducted experiments.

But, at the moment Kim proposal is an hypothesis.

7 0
4 years ago
Ozone (O 3) in the atmosphere can react with nitric oxide (NO): O 3(g) + NO(g) → NO 2(g) + O 2(g). Calculate the ΔG° for this re
Mandarinka [93]

Answer:

ΔG°  = 1022. 8 kJ

Explanation:

ΔH° = –199 kJ/mol

ΔS° = –4.1 J/K·mol

T = 25°C = 25 + 273 = 298K (Converting to kelvin temperature)

ΔG° = ?

The relationship between these varriables are;

ΔG° = ΔH°  - TΔS°

ΔG° = –199 - 298 (–4.1)

ΔG° = -199 + 1221.8

ΔG°  = 1022. 8 kJ

6 0
3 years ago
If 9.0 L of NO are reacted with excess O2 at STP, what is the volume in liters of the NO2 produced? Methane, the principal compo
d1i1m1o1n [39]

9 L of the NO2 was produced if 9.0 L of NO are reacted with excess O_2 at STP.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

According to the question, the given reaction is -

2NO(g) + O₂(g)--->2NO₂(g)

Since at STP one mole of a gas occupies the volume of 22.4 L.

As given in the question -

9 L of NO, i.e .

22.4 L = 1 mol

1 L = \frac{1}{22.4 mol}

For 9 L =\frac{1 X 9L}{22.4 mol} = 0.40 mol

From the chemical reaction,

The Oxygen is in excess, hence NO becomes the limiting reagent, and will determine the moles of the product.

Hence,  2 moles of NO will produce 2 moles of NO₂.

Therefore, 0.40 mol of NO will produce 0.40 mol of NO₂.

Hence, the volume of NO₂ can be calculated as -

1 mol = 22.4 L

0.40 mol = 0.40 X 22.4 L = 9 L

Hence, 9 L of the NO₂ was produced.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

3 0
2 years ago
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