Five. The measurement 50,600 mg has five significant digits.
I presume that you are using the comma as a decimal separator.
The <em>rules for significant figures</em> are
1. Nonzero digits are always significant.
2. Any zeros between two significant digits are significant.
3. Final or trailing zeros are significant only if they are to the right of a decimal point.
• According to Rule 1, the <em>5 and 6</em> are significant.
• According to Rule 2, the <em>0 between the 5 and 6</em> is significant
• According to Rule 3, the <em>final two zeros</em> are significant.
Thus, there are five significant digits in the measurement 50,600 mg.
Note: If the comma is a thousands separator, the number has only three significant digits.
66.2 kg 1) 25 kg H X (1 mol / 2.016) X (16.043 / 1 mol)= 66.2kg I am sorry if this is not what you looking for my friend
<span>This question cannot be answered in actual centimeters unless at least one edge has a known length however it can be written as (length^3) or (length cubed). As an example if the sample of gold cube had one length of 3cm then all lengths would be 3cm on the cube.</span>
<h3>
Answer:</h3>
56.11 g/mol
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Compound] KOH
<u>Step 2: Identify</u>
[PT] Molar Mass of K - 39.10 g/mol
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mass of H - 1.01 g/mol
<u>Step 3: Find</u>
39.10 + 16.00 + 1.01 = 56.11 g/mol
