Give the name of the following molecule. A compound with a total of six carbons with a double bond and the rest single bonds. Th
ere is a chain of five carbons across the bottom with a double bond between the third and fourth carbons when counting form left to right. There in a methyl group branching off of the middle carbon.
1 answer:
Answer:
The name of given molecule is 3-Methylpent-2-ene.
Explanation:
First of all a carbon chain of five carbons was drawn. Then a double bond was made between carbon 3 and 4 (starting from left). A methyl group was drawn at middle carbon which is at position 3.
Molecule sketched was named as,
1) A longest chain containing double bond was selected and numbering was started from the end closest to double bond. Hence,
2-Pentene or Pent-2-ene
2) The position of substituent was specified before the parent name, Hence,
3-Methyl-2-Pentene or 3-Methylpent-2-ene
The name of given molecule is 3-Methylpent-2-ene.
Explanation:
First of all a carbon chain of five carbons was drawn. Then a double bond was made between carbon 3 and 4 (starting from left). A methyl group was drawn at middle carbon which is at position 3.
Molecule sketched was named as,
1) A longest chain containing double bond was selected and numbering was started from the end closest to double bond. Hence,
2-Pentene or Pent-2-ene
2) The position of substituent was specified before the parent name, Hence,
3-Methyl-2-Pentene or 3-Methylpent-2-ene
You might be interested in
Hello!
Find the Energy of the Photon by Planck's Equation, given:
E (photon energy) =? (in Joule)
h (Planck's constant) =
f (radiation frequency) =
Therefore, we have:
I Hope this helps, greetings ... DexteR! =)