All categories

3 years ago

A gas has a volume of 6.46L at 1.06 atm and 77.2°C. What is the volume of the gas (in L) at STP

Chemistry

2 answers:

galben [10]3 years ago

5 0

Answer:

5.35

Explanation:

Svetlanka [38]3 years ago

4 0

Answer:

5.34 L

Explanation:

1.06×6.46×273/350.2×1

almost postive this is correct

You might be interested in

A gas occupies 14.3 liters at a pressure of 45.0 mm Hg. What is the volume when the pressure is increased to

Simora [160]

Answer:

P1V1= P2V2

Explanation:

Inverse relationship

V2 = V1 X P1/P2

V2= 14.3 L x 45.0 mm Hg/63.0 mmHg= 8.99

8 0

2 years ago

Write uses of Co-60 .

ivolga24 [154]

Answer:

Cobalt Sources

Cobalt-60 is used as a radiation source in many common industrial applications, such as in leveling devices and thickness gauges. It is also used for radiation therapy in hospitals. Accidental exposures may occur as the result of loss or improper disposal of medical and industrial radiation sources.

Explanation:

4 0

2 years ago

Read 2 more answers

Of the elements fe li te u and he which are considered group b elements

VLD [36.1K]

A group B element is Fe

4 0

2 years ago

The activation energy for a reaction is changed from 184 kJ/mol to 59.0 kJ/mol at 600. K by the introduction of a catalyst. If t

11111nata11111 [884]

Answer:

The catalyzed reaction will take 2.85 seconds to occur.

Explanation:

The activation energy of a reaction is given by:

$k = Ae^{-\frac{E_{a}}{RT}}$

For the reaction without catalyst we have:

$k_{1} = Ae^{-\frac{E_{a_{1}}}{RT}}$ (1)

And for the reaction with the catalyst:

$k_{2} = Ae^{-\frac{E_{a_{2}}}{RT}}$ (2)

Assuming that frequency factor (A) and the temperature (T) are constant, by dividing equation (1) with equation (2) we have:

$\frac{k_{1}}{k_{2}} = \frac{Ae^{-\frac{E_{a_{1}}}{RT}}}{Ae^{-\frac{E_{a_{2}}}{RT}}}$

$\frac{k_{1}}{k_{2}} = e^{\frac{E_{a_{2}} - E_{a_{1}}}{RT}$

$\frac{k_{1}}{k_{2}} = e^{\frac{59.0 \cdot 10^{3}J/mol - 184 \cdot 10^{3} J/mol}{8.314 J/Kmol*600 K} = 1.31 \cdot 10^{-11}$

Since the reaction rate is related to the time as follow:

$k = \frac{\Delta [R]}{t}$

And assuming that the initial concentrations ([R]) are the same, we have:

$\frac{k_{1}}{k_{2}} = \frac{\Delta [R]/t_{1}}{\Delta [R]/t_{2}}$

$\frac{k_{1}}{k_{2}} = \frac{t_{2}}{t_{1}}$

$t_{2} = t_{1}\frac{k_{1}}{k_{2}} = 6900 y*1.31 \cdot 10^{-11} = 9.04 \cdot 10^{-8} y*\frac{365 d}{1 y}*\frac{24 h}{1 d}*\frac{3600 s}{1 h} = 2.85 s$

Therefore, the catalyzed reaction will take 2.85 seconds to occur.

I hope it helps you!

4 0

2 years ago

Which of the following is a type of physical change.

trapecia [35]

Answer:

B. a change in their state or substance

Explanation:

A change of state consists of a physical process in which the structure of the substance changes, its appearance. EXAMPLE: in the merger, the solid state becomes liquid, changes the rearrangement of particles from being highly compacted to being less compact.

6 0

3 years ago

A gas has a volume of 6.46L at 1.06 atm and 77.2°C. What is the volume of the gas (in L) at STP​

A gas has a volume of 6.46L at 1.06 atm and 77.2°C. What is the volume of the gas (in L) at STP