Conservation
conservation is the act of protecting animals and resources for current and future generations
There will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.There will be needed mL of
Why?
In order to calculate how many milliliters are needed to obtain 16.1 grams of the salt given its concentration, we first need to find its chemical formula which is the following:
Now that we know the chemical formula of the substance, we need to find its molecular mass. We can do it by the following way:
We have that the molecular mass of the substance will be:
Therefore, knowing the molecular mass of the substance, we need to calculate how many mols represents 16.1 grams of the same substance, we can do it by the following way:
Finally, if we need to calculate how many milliliters are needed, we need to use the following formula:
Now, substituting and calculating, we have:
Henc, there will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.
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<span>Mass is a property that determines how much effort it takes to change somethings velocity. Weight is how much downward force does something exert in a gravitational field which is just the amount of gravity time the mass of an object. We use mass interchangeable with weight because everything on earth experiences the same amount of gravity or close to it, and so something that weighs twice as much as something else also has twice as much mass as that something else. Weight can actually vary for the same mass here on earth the strength of gravity changes from one place to another by small amounts, not enough to ruin your cooking recipe instructions, and weight can change dramatically for something that is falling, the strength of gravity for astronauts in orbit is not much reduced in comparison to here on earth, if there was no gravity they wouldn't go around the earth, they are weightless because they are falling and have enough sideways velocity to keep missing the earth, but their mass has not changed, it still requires effort to get them moving or to stop them.
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Answer:
Average atomic mass = 14.0067 amu.
Explanation:
Given data:
Abundance of 1st isotope = 99.63%
Atomic mass of 1st isotope = 14.003 amu
Abundance of 2nd isotope = 0.37%
Atomic mass of 2nd isotope = 15.000 amu
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (99.63×14.003)+(0.37×15.000) /100
Average atomic mass = 1395.119 + 5.55 / 100
Average atomic mass = 1400.67 / 100
Average atomic mass = 14.0067 amu.
