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4 years ago

Josie sees lightning off in the distance. A few seconds later she hears thunder. What can Josie conclude?

Physics

2 answers:

Naddik [55]4 years ago

8 0

Light wave travel faster than sound waves

GREYUIT [131]4 years ago

5 0

Hello there.

<span>Josie sees lightning off in the distance. A few seconds later she hears thunder. What can Josie conclude?

</span><span>Light waves travel faster than sound waves.
</span>

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Water is pouring into a conical tank at the rate of 8 cubic feet per minute. If the height of the tank is 10 feet and the radius

iren [92.7K]

Answer:

$\frac{25}{8\pi}ft/min$

Explanation:

We are given that

$\frac{dV}{dt}=8 ft^3/min$

Height of tank=h=10 ft

Radius of tank, r=4 feet

We have to find the dh/dt when the water is 4 feet deep.

$\frac{r}{h}=\frac{4}{10}=\frac{2}{5}$

$r=\frac{2}{5}h$

Volume of cone , $V=\frac{1}{3}\pi r^2 h$

Substitute the values

Volume of cone , $V=\frac{1}{3}\pi(\frac{2}{5}h)^2h=\frac{4}{75}\pi h^3$

Differentiate w.r.t t

$\frac{dV}{dt}=\frac{12}{75}\pi\times h^2\times \frac{dh}{dt}$

Substitute the values

$8=\frac{12}{75}\times\pi (4)^2\times \frac{dh}{dt}$

$\frac{dh}{dt}=\frac{8\times 75}{12\times 16\pi}=\frac{25}{8\pi}ft/min$

3 0

4 years ago

A coiled telephone cord forms a spiral with 90.0 turns, a diameter of 1.30 cm, and an unstretched length of 57.0 cm. Determine t

Vinvika [58]

Answer:

2.36 μ H

Explanation:

Given,

Number of turns= 90

diameter = 1.3 cm = 0.013 m

unscratched length = 57 cm = 0.57 m

Area, A = π r²

= π x 0.0065² = 1.32 x 10⁻⁴ m²

we know,

$L = \dfrac{\mu_0N^2A}{l}$

$L = \dfrac{4\pi \times 10^{-7}\times 90^2\times 1.32\times 10^{-4}}{0.57}$

L = 2.36 μ H

Hence, the inductance of the unstretched cord is equal to 2.36 μ H

8 0

3 years ago

Help with TEST pls!!

Westkost [7]

Answer:

12. D.

13. C.

14. H.

15. F.

16. G.

17. A.

18. D.

19. B.

20. C.

Hope this helps :)

Explanation:

8 0

3 years ago

A train travels at 270 km in 3 hours . what is the speed of the train?

Ann [662]

$270 \div 3 = 90km / h$

3 0

3 years ago

Read 2 more answers

The latent heat of fusion of water at 0 °C is 6.025 kJ mol'' and the molar heat

Scilla [17]

Answer:

$\Delta H_{tot} = 2258.025\,kJ$

Explanation:

The amount of heat released from water is equal to the sum of latent and sensible heats. Let suppose that water is initially at a temperature of $25^{\circ}C$ . Then:

$\Delta H_{tot} = \Delta H_{s, w} + \Delta H_{f,w} + \Delta H_{s,i}$

$\Delta H_{tot} = n\cdot (c_{w}\cdot \Delta T_{w} + L_{f} + c_{i}\cdot \Delta T_{i})$

Finally, the amount of heat released from water is now computed by replacing variables:

$\Delta H_{tot} = (1\,mol)\cdot \left[\left(75.3\,\frac{kJ}{mol\cdot K} \right)\cdot (25^{\circ}C-0^{\circ}C)+ 6.025\,\frac{kJ}{mol} + \left(37.7\,\frac{kJ}{mol\cdot K} \right)\cdot (0 + 10^{\circ}C)\right]$ $\Delta H_{tot} = 2258.025\,kJ$

4 0

3 years ago