Answer:
see explanation
Step-by-step explanation:
Given
A = 
bh
a. substitute b = 6 and h = 5 into the formula
A = × 6 × 5 = × 30 = 15 units²
b.
Multiply both sides of the formula by 2
2A = bh, that is
bh = 2A ← divide both sides by b
h = 
= 
= 
= 8
c
Using
bh = 2A ← divide both sides by h
b = 
= 
= 
= 6
Your answer is B. Using the distributive property, 3/4 • 5z equals 15/4z, which can't be simplified. Then 3/4 of 16 is 12. If you divide 16 by 4 (the denominator) and then multiply by 3 (the numerator) that yields your answer.
Answer:
The values of x for which the model is 0 ≤ x ≤ 3
Step-by-step explanation:
The given function for the volume of the shipping box is given as follows;
V = 2·x³ - 19·x² + 39·x
The function will make sense when V ≥ 0, which is given as follows
When V = 0, x = 0
Which gives;
0 = 2·x³ - 19·x² + 39·x
0 = 2·x² - 19·x + 39
0 = x² - 9.5·x + 19.5
From an hint obtained by plotting the function, we have;
0 = (x - 3)·(x - 6.5)
We check for the local maximum as follows;
dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0
6·x² - 38·x + 39 = 0
x² - 19/3·x + 6.5 = 0
x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2
∴ x = 1.288, or 5.045
At x = 1.288, we have;
V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99
V ≈ 22.99 in.³
When x = 5.045, we have;
V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023
Therefore;
V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5
The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.
