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sladkih [1.3K]
3 years ago
6

A scuba tank, when fully submerged, displaces 15.7 l of seawater. the tank itself has a mass of 13.7 kg and, when "full," contai

ns 3.00 kg of air. the density of seawater is 1025 kg/m3. assume that only its weight and the buoyant force act on the tank.
Physics
1 answer:
julia-pushkina [17]3 years ago
7 0
The problem is asking for the buoyant force.
The first step is to know the weights of the tank and air. Tank = 13.7 * 9.8 = 134.26 N Air = 3 * 9.8 = 29.4 N Total weight of the tank and air is 163.66 N 
To know the buoyant force, we must convert 15.7 liters to cubic meters. 
1 liter = 1000 ml = 1000 cm^3 1 m = 100 cm 1 m^3= 1,000,000 cm^3 One liter = 1000 divided by 1,000,000 = 0.001 m^3 V = 15 * 0.001 = 0.015 m^3 
Then compute for the buoyant force:Buoyant force = 0.015 * 1025 * 9.8 = 150.675 N
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Answer:

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V_{t}=\frac{2 \mathrm{R}^{2}(\rho-\sigma) \mathrm{g}}{9 \eta}

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\mathrm{V}_{\mathrm{t}}=\frac{2 \times 0.0024^{2}(7800-1360) 9.8}{9 \times 6}

\mathrm{V}_{\mathrm{t}}=\frac{0.0048 \times 6440 \times 9.8}{54}

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\mathrm{V}_{\mathrm{t}}=5.609 \mathrm{m} / \mathrm{s}

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