In a stronger gravitational field a given mass will have a larger weight.
Answer:
μ = tan θ
Explanation:
For this exercise let's use the translational equilibrium condition.
Let's set a datum with the x axis parallel to the plane and the y axis perpendicular to the plane.
Let's break down the weight of the block
sin θ = Wₓ / W
cos θ = W_y / W
Wₓ = W sin θ
W_y = W cos θ
The acrobat is vertically so his weight decomposition is
sin θ = = wₐₓ / wₐ
cos θ = wₐ_y / wₐ
wₐₓ = wₐ sin θ
wₐ_y = wₐ cos θ
let's write the equilibrium equations
Y axis
N- W_y - wₐ_y = 0
N = W cos θ + wₐ cos θ
X axis
Wₓ + wₐ_x - fr = 0
fr = W sin θ + wₐ sin θ
the friction force has the formula
fr = μ N
fr = μ (W cos θ + wₐ cos θ)
we substitute
μ (Mg cos θ + mg cos θ) = Mgsin θ + mg sin θ
μ =
μ = tan θ
this is the minimum value of the coefficient of static friction for which the system is in equilibrium.
In thicker materials the particles can move more easily, therefore the resistance has to decrease.
Hence Option (b) is correct.
Resistivity, which is sometimes represented by the Greek letter rho, is quantitatively equal to a specimen's resistance R times its cross-sectional area A times its length.
ρ = R × A/ l
R = ρ × l/ A
It means the Resistance of the material is inversely proportional to the area of the material.
As the area of the material increases, the resistance decreases and vice versa.
Hence, In thicker particles, there is a greater area available and that's why resistance has to decrease so that particles can move more easily.
Hence, Option (b) is correct.
Learn more about Resistance & Resistivity here brainly.com/question/13735984
#SPJ1
The aqueous solution will most likely be a base.