Answer:
The voltage of the battery
Answer:
ΔX = λ = 0.68 m
Explanation:
Wave speed is related to wavelength and frequency by the equation
v = λ f
where the speed of sound is 340 m / s
λ = v / f
λ = 340/500
λ = 0.68 m
this is the wavelength, it is the minimum distance for which the wave epitates its movement, which is equal to the distance between two consecutive compressions of the sound
ΔX = λ = 0.68 m
The question here would be what is the volume of the room. The density of air that is given has no use. We simply multiply the dimensions given of the room to determine the volume.
<span>43.0m × 18.0m × 15.0m = 11610m^3 ( 3.28 ft / 1 m)^3 = 4.09 x 10^5 ft^3</span>
Answer:
The time it can operate between chargins in minutes is

Explanation:
Given:
,
, 
a). The rotational kinetic energy






b). The power average 0.8kW un range time can be find

Solve to t'



Answer:
The dynamo produces Alternating Current output, so in theory yes, it should work in reverse if Alternating Current is input.