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3 years ago

Acceleration of a refrigerator 30s after a person begins pushing it at a force of 400 N

1 answer:

6 0

Question: Find acceleration of a refrigerator 30s after a person begins pushing it at a force of 400 N, If the mass of the refrigerator is 10 kg.

Answer:

40 m/s²

Explanation:

Applying,

F = ma................Equation 1

Where F = Force applied to the refrigerator, m = mass of the refrigerator, a = acceleration of the refrigerator.

make a the subject of the equation

a = F/m............ Equation 2

From the question,

Given: F = 400 N, m = 10 kg

Substitute these values into equation 2

a = 400/10

a = 40 m/s²

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igor_vitrenko [27]

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3 years ago

the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67

baherus [9]

Answer:

$\theta_c = 36.78^o$

Explanation:

The relationship between the refractive index and the critical angle is given as follows:

$\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )$

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3 years ago