Which of the following describes a product concept?
1 answer:
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Answer:
volume of biological sludge = 28.566 m³ per day
Explanation:
given data
mass of solid = 7240 kg/day
initial moisture content = 78%
solution
here percentage of solid will be
% of solid = 100 - initial moisture content
% of solid = 100 - 78 = 22 %
so that
mass of sludge produced = kg per day
put her value
mass of sludge produced = kg
mass of sludge produced = 32909.09 kg
so
specific gravity of sludge =
and as we know that
= 1.152
so that
density of sludge = S sludge × density of water
density of sludge = 1.152 × 1000
density of sludge = 1152 kg/m³
so that
volume of biological sludge =
volume of biological sludge =
volume of biological sludge = 28.566 m³ per day
Answer:
The mass flow rate of steam m=5.4 Kg/s
Explanation:
Given:
At the inlet of turbine P=10 MPa ,T=500 C
AT the exit of turbine P=10 KPa ,x=0.9
Required power=5 MW
From steam table
<u> At 10 MPa and 500 C:</u>
h=3374 KJ/Kg ,s=6.59 KJ/Kg-K (Super heated steam table)
<u>At 10 KPa:</u>
=2675.1 KJ/Kg,
=417.51 KJ/Kg
= 7.3 KJ/Kg-K ,
=1.3 KJ/Kg-K
So enthalpy of steam at the exit of turbine
h=
Now by putting the values
h= 417.51+0.9(2675.1- 417.51) KJ/Kg
h=2449.34 KJ/Kg
Lets take m is the mass flow rate of steam
So
m=5.4 Kg/s
So the mass flow rate of steam m=5.4 Kg/s