Answer:
The time necessary to purge 95% of the NaOH is 0.38 h
Explanation:
Given:
vfpure water(i) = 3 m³/h
vNaOH = 4 m³
xNaOH = 0.2
vfpure water(f) = 2 m³/h
pwater = 1000 kg/m³
pNaOH = 1220 kg/m³
The mass flow rate of the water is = 3 * 1000 = 3000 kg/h
The mass of NaOH in the solution is = 0.2 * 4 * 1220 = 976 kg
When the 95% of the NaOH is purged, thus the NaOH in outlet is = 0.95 * 976 = 927.2 kg
The volume of NaOH in outlet after time is = 927.2/1220 = 0.76 m³
The time required to purge the 95% of the NaOH is = 0.76/2 = 0.38 h
Answer:
//Program was implemented using C++ Programming Language
// Comments are used for explanatory purpose
#include<iostream>
using namespace std;
unsigned int second_a(unsigned int n)
{
int r,sum=0,temp;
int first;
for(int i= 1; I<=n; i++)
{
first = n;
//Check if first digit is 3
// Remove last digit from number till only one digit is left
while(first >= 10)
{
first = first / 10;
}
if(first == 3) // if first digit is 3
{
//Check if n is palindrome
temp=n; // save the value of n in a temporary Variable
while(n>0)
{
r=n%10; //getting remainder
sum=(sum*10)+r;
n=n/10;
}
if(temp==sum)
cout<<n<<" is a palindrome";
else
cout<<n<<" is not a palindrome";
}
}
}
Explanation:
The above code segments is a functional program that checks if a number that starts with digit 3 is Palindromic or not.
The program was coded using C++ programming language.
The main method of the program is omitted.
Comments were used for explanatory purpose.
Answer:
They are use to hold garment or fabric pieces together before pernament stitches are made
Answer:
8 for dual-op-amp package, and 14 for quad-op-amp
Explanation;
This is because every op-amp has 2 input terminal 4 pns
So one output terminal that is 2 pins which are required for power
and the same for a minumum number of pins required by quad op amp which is 14
Answer:
a)COP=5.01
b)
KW
c)COP=6.01
d)
Explanation:
Given
= -12°C,
=40°C
For refrigeration
We know that Carnot cycle is an ideal cycle that have all reversible process.
So COP of refrigeration is given as follows
,T in Kelvin.
a)COP=5.01
Given that refrigeration effect= 15 KW
We know that 
RE is the refrigeration effect
So
5.01=
b) KW
For heat pump
So COP of heat pump is given as follows
,T in Kelvin.
c)COP=6.01
In heat pump
Heat rejection at high temperature=heat absorb at low temperature+work in put
Given that 
KW
We know that 
d)
