Answer and Explanation:
• 1 thread awaits the incoming request
• 1 thread responds to the request
• 1 thread reads the hard disk
A multithreaded file server is better than a single-threaded server and a finite-state machine server because it provides better response compared to the rest and can make use of the shared Web data.
Yes, there are circumstances in which a single-threaded server might be better. If it is designed such that:
- the server is completely CPU bound, such that multiple threads isn't needed. But it would account for some complexity that aren't needed.
An example is, the assistance number of a telephone directory (e.g 7771414) for an community of say, one million people. Consider that each name and telephone number record is sixty-four characters, the whole database takes 64 MB, and can be easily stored in the server's memory in order to provide quick lookup.
NOTE:
Multiple threads lead to operation slow down and no support for Kernel threads.
Answer:
B A and C
Explanation:
Given:
Specimen σ
σ
A +450 -150
B +300 -300
C +500 -200
Solution:
Compute the mean stress
σ
= (σ + σ)/2
σ
= (450 + (-150)) / 2
= (450 - 150) / 2
= 300/2
σ = 150 MPa
σ
= (300 + (-300))/2
= (300 - 300) / 2
= 0/2
σ = 0 MPa
σ
= (500 + (-200))/2
= (500 - 200) / 2
= 300/2
σ = 150 MPa
Compute stress amplitude:
σ
= (σ - σ)/2
σ
= (450 - (-150)) / 2
= (450 + 150) / 2
= 600/2
σ = 300 MPa
σ
= (300- (-300)) / 2
= (300 + 300) / 2
= 600/2
σ = 300 MPa
σ
= (500 - (-200))/2
= (500 + 200) / 2
= 700 / 2
σ = 350 MPa
From the above results it is concluded that the longest fatigue lifetime is of specimen B because it has the minimum mean stress.
Next, the specimen A has the fatigue lifetime which is shorter than B but longer than specimen C.
In the last comes specimen C which has the shortest fatigue lifetime because it has the higher mean stress and highest stress amplitude.
Answer:
(a) T₂ =747.5 and K= 474.5 °C (b) 330.178 kJ/kg
Explanation:
Solution
T₁ = 35°C = 308
the first step to take is to Use the Table A-17: Ideal gas properties for air:
Now,
At T₁ = 308 K
V₁ = 217.67 + [308-305/310-305] (221.25 -217.67)
So,
V₁ =219.818 kJ/kg
Thus,
Vr₁ = 596 + [308-305/310-305] (572.3 - 596)
= 581.78
so,
Vr₂/Vr₁ = 1/10
Vr₂ =58.178
Applying Table A-17, at Vr₂ = 58.178
Then,
(a) T₂ = 740 + [58.178 - 59.82/57.63 -59.82] (750 -740)
T₂ = 747.5 and K = 474.5 °C
V₂ =544.02 + [58.178 - 59.82/57.63 -59.82] (551.99 - 544.02)
so,
V₂ =549.996 kJ/kg
Hence,
(b) q - w = v₂ -v₁
= 0 -w = 549.996- 219.818
w = 330.178 kJ/kg
Answer: National anthem contributed to the development of unity diversity in nepal; The Sayaun Thunga Phool Ka was officially adopted as national anthem of Nepal on 3rd August 2007. This anthem which means made of hundred flowers strongly portrays the great unity and diversity of Nepalese people.
Explanation:
