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77julia77 [94]
3 years ago
12

A store is having a sale on jelly beans and almonds. For 2 pounds of jellybeans and 6 pounds of almonds the total cost is $12. F

or 5 pounds of jellybeans and 3 pounds of almonds the total cost is $15. Find the cost for each pound of jellybeans in each pound of find the cost for each pound of jellybeans in each pound of almonds
Mathematics
2 answers:
miskamm [114]3 years ago
8 0

Answer:

1 pound of jellybeans costs $2.25

and 1 pound of almond costs $1.25

Step-by-step explanation:

Say jellybeans is j and almonds is a. The question can be interpreted as

2j + 6a = 12 ....................... equation 1

5j + 3a = 15 ....................... equation 2

Using elimination method for the above simultaneous equation, lets multiply equation 1 by the coefficient of j in equation 2 and vice versa

(2j + 6a = 12)*5 .......................... eqn 3

(5j + 3a = 15)*2 .......................... eqn 4

Then we will have

10j + 30a = 60 ........................... eqn 5

10j + 6a   = 30 ........................... eqn 6

Subtract equation 6 from equation 5 to eliminate j, we will have

24a = 30

Divide both side by 24, we will have

a = 30/24

a = 1.25

Therefore 1 pound of almonds cost $1.25

To get the price of jellybeans, we substitute for a in any of the equations above

2j + 6a = 12

2j + 6(1.25) = 12

2j + 7.5 = 12        Collecting the like terms, we will have

2j = 12 - 7.5

2j = 4.5               Divide both sides by 2, we will have

j = 2.25

Therefore the cost of 1 pound jellybeans is $2.25

stich3 [128]3 years ago
5 0

Answer:

mom

Step-by-step explanation:

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A rectangular piece of plywood has a diagonal which measures two feet more than the width. The length of the plywood is twice th
icang [17]

Answer:

The length of the plywood's diagonal(to the nearest tenth) is, 3.6 and 1.4

Step-by-step explanation:

let l be the length and w be the width of the rectangle respectively;

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\sqrt{(2w)^2+w^2} = w+5

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4w^2+w^2 = (w+2)^2

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4w^2= 4w + 4

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w^2-w-1 =0                         ......[2]

The quadratic equation is in the form  of ax^2+bx+c = 0

the solution is given by:  x = \frac{-b \pm\sqrt{b^2-4ac}}{2a}

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5 0
3 years ago
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Vesna [10]

I assume you're asking to solve for the n-th term in the sequence, a_n.

From the given recursive rule,

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and by substitution,

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Similarly,

a_n = a_{n-1} + 2 \implies a_{n-2} = a_{n-3} + 2

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The pattern continues, so that we can write the n-th term in terms of the 1st one:

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So the first few terms of the sequence are

{10, 12, 14, 16, 18, 20, …}

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