Having your space clean. have on close toed shoes. have your hair pulled back into a ponytail. keep ur work space clean. wear gloves and goggles. do not have on droopy clothes. follow the steps on the board and double check them.
Answer
given,
y(x,t)= 2.20 mm cos[( 7.02 rad/m )x+( 743 rad/s )t]
length of the rope = 1.33 m
mass of the rope = 3.31 g
comparing the given equation from the general wave equation
y(x,t)= A cos[k x+ω t]
A is amplitude
now on comparing
a) Amplitude = 2.20 mm
b) frequency =
![f = \dfrac{\omega}{2\pi}](https://tex.z-dn.net/?f=f%20%3D%20%5Cdfrac%7B%5Comega%7D%7B2%5Cpi%7D)
![f = \dfrac{743}{2\pi}](https://tex.z-dn.net/?f=f%20%3D%20%5Cdfrac%7B743%7D%7B2%5Cpi%7D)
f = 118.25 Hz
c) wavelength
![k= \dfrac{2\pi}{\lambda}](https://tex.z-dn.net/?f=k%3D%20%5Cdfrac%7B2%5Cpi%7D%7B%5Clambda%7D)
![\lambda= \dfrac{2\pi}{k}](https://tex.z-dn.net/?f=%5Clambda%3D%20%5Cdfrac%7B2%5Cpi%7D%7Bk%7D)
![\lambda= \dfrac{2\pi}{7.02}](https://tex.z-dn.net/?f=%5Clambda%3D%20%5Cdfrac%7B2%5Cpi%7D%7B7.02%7D)
![\lambda= 0.895\ m](https://tex.z-dn.net/?f=%5Clambda%3D%200.895%5C%20m)
d) speed
![v = \dfrac{\omega}{k}](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B%5Comega%7D%7Bk%7D)
![v = \dfrac{743}{7.02}](https://tex.z-dn.net/?f=v%20%3D%20%5Cdfrac%7B743%7D%7B7.02%7D)
v = 105.84 m/s
e) direction of the motion will be in negative x-direction
f) tension
![T = \dfrac{v^2\ m}{L}](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7Bv%5E2%5C%20m%7D%7BL%7D)
![T = \dfrac{(105.84)^2\times 3.31 \times 10^{-3}}{1.33}](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B%28105.84%29%5E2%5Ctimes%203.31%20%5Ctimes%2010%5E%7B-3%7D%7D%7B1.33%7D)
T = 27.87 N
g) Power transmitted by the wave
![P = \dfrac{1}{2}m\ v \omega^2\ A^2](https://tex.z-dn.net/?f=P%20%3D%20%5Cdfrac%7B1%7D%7B2%7Dm%5C%20v%20%5Comega%5E2%5C%20A%5E2)
![P = \dfrac{1}{2}\times 0.00331\times 105.84\times 743^2\ 0.0022^2](https://tex.z-dn.net/?f=P%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%200.00331%5Ctimes%20105.84%5Ctimes%20743%5E2%5C%200.0022%5E2)
P = 0.438 W
Answer:
93 km/h
Explanation:
Given that a bus took 8 hours to travel 639 km. For the first 5 hours, it travelled at an average speed of 72 km/h
Let the first 5 hours journey distance = F
From the formula of speed,
Speed = distance/time
Substitute speed and time
72 = F/5
F = 72 × 5 = 360 km
The remaining distance will be:
639 - 360 = 279km
The remaining time will be:
8 - 5 = 3 hours
Speed = 279/3
Speed = 93 km/h
Therefore, the average speed for the remaining time of the journey is equal to 93 km/h
<span>AnalStage. </span>According to Freud, a<span>dults fixated in this area could feel constantly out
of control or could need to be in control all the time. Pleasure focus
is on the anus, which occurs when a child learns to control bladder and bowel
movements. Fixation in this area can be caused from struggles during potty
training.</span>
Answer:
270 mi/h
Explanation:
Given that,
To the south,
v₁ = 300 mi/h, t₁ = 2 h
We can find distance, d₁
![d_1=v_1\times t_1\\\\d_1=300\times 2\\\\d_1=600\ \text{miles}](https://tex.z-dn.net/?f=d_1%3Dv_1%5Ctimes%20t_1%5C%5C%5C%5Cd_1%3D300%5Ctimes%202%5C%5C%5C%5Cd_1%3D600%5C%20%5Ctext%7Bmiles%7D)
To the north,
v₂ = 250 mi/h, d₂ = 750 miles
We can find time, t₂
![t_2=\dfrac{d_2}{v_2}\\\\t_2=\dfrac{750\ \text{miles}}{250\ \text{mi/h}}\\\\t_2=3\ h](https://tex.z-dn.net/?f=t_2%3D%5Cdfrac%7Bd_2%7D%7Bv_2%7D%5C%5C%5C%5Ct_2%3D%5Cdfrac%7B750%5C%20%5Ctext%7Bmiles%7D%7D%7B250%5C%20%5Ctext%7Bmi%2Fh%7D%7D%5C%5C%5C%5Ct_2%3D3%5C%20h)
Now,
Average speed = total distance/total time
![V=\dfrac{d_1+d_2}{t_1+t_2}\\\\V=\dfrac{600+750}{2+3}\\\\V=270\ \text{mi/h}](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7Bd_1%2Bd_2%7D%7Bt_1%2Bt_2%7D%5C%5C%5C%5CV%3D%5Cdfrac%7B600%2B750%7D%7B2%2B3%7D%5C%5C%5C%5CV%3D270%5C%20%5Ctext%7Bmi%2Fh%7D)
Hence, the average speed for the trip is 270 mi/h.