D, 0.140 liters! Hang on a sec and I'll show you a trick I use.
Answer:
D)evaluating a solution
Explanation:
In this scenario, the next logical step would be evaluating a solution. This is because Jasper and Samantha have already identified the problem/need which is that the robot needs to be able to move a 10-gram weight at least 2 meters and turn in a circle. They also designed and implemented a solution because they have already built the robot. Therefore the only step missing is to evaluate and make sure that the robot they built is able to complete the requirements.
"60 kg" is not a weight. It's a mass, and it's always the same
no matter where the object goes.
The weight of the object is
(mass) x (gravity in the place where the object is) .
On the surface of the Earth,
Weight = (60 kg) x (9.8 m/s²)
= 588 Newtons.
Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to 5R from the center, the gravity out there is
(1R/5R)² = (1/5)² = 1/25 = 0.04 of its value on the surface.
The object's weight would also be 0.04 of its weight on the surface.
(0.04) x (588 Newtons) = 23.52 Newtons.
Again, the object's mass is still 60 kg out there.
___________________________________________
If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink.
You are being planted with sloppy, inaccurate, misleading
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.
Displacement = (distance between start and end points) in the direction of (direction from start to end point). Distance = (11.3-3.38)= 7.92 m. Direction = the negative 'x' direction.
Answer:
<em>a) 2.63 : 1</em>
<em>b) 143.13 rpm</em>
Explanation:
initial angular velocity ω' = 130 rpm
final angular velocity ω = 342 rpm
recall that angular momentum = ωI
where I is the moment of inertia.
for the initial spinning condition, we take moment of inertial = I'
for final spinning condition, we take moment of inertia = I
initial angular momentum = ω'I' = 130 I'
final angular momentum = ωI = 342 I
according to conservation of angular momentum, initial angular momentum must be equal to the final angular momentum, therefore
342 I = 130 I'
ratio of initial moment of inertia to final moment of inertia = I'/I
==> I'/I = 342/130 ≅ <em>2.63 : 1</em>
b) to achieve a final angular velocity of of 375 rpm, her initial velocity will have to be
2.63 = 375/ω'
ω' = 375/2.63 = <em>143.13 rpm</em>
