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Pepsi [2]
3 years ago
11

The pressure at the center of the earth is probably greater than 3x106 atm, and the temperature there is about 4000 °C. What is

the change in the Gibbs function of reaction on going from crust to core for a reaction in which Vm = 1 cm3 mol-1 and Sm = 2.1 J K-1 mol-1
Chemistry
1 answer:
andrezito [222]3 years ago
7 0

Answer:

The change in the Gibbs function of reaction on going from crust to core, dG=291442.4 J/mol

Explanation:

dG=vdp-sdT

Where T is the temperature .

P is the pressure.

S is entropy

V= 1cm3 =10-6 m3

P= 3*10∧6 atm = 3*10∧11 pa

The temperature at the center of the earth, Tc = 4*103 °C. : The temperature at the sufrace (crust) of the earth, Ts =298K.

Subistuting the values

dG = (10-6 *(3*1011-105) - (2.1(4373-298))

dG=291442.4 J/mol.

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Answer:

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1. Find Molar Mass

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First, find the molar masses of the individual elements in the compound: iron (Fe) and chlorine (Cl).

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  • Cl:  35.45 g/mol

There are 3 atoms of chlorine, denoted by the subscript after Cl. Multiply the molar mass of chlorine by 3 and add iron's molar mass.

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This number tells us the grams of FeCl₃ in 1 mole.

2. Calculate Moles

Use the number as a ratio.

\frac{162.19 \ g \ FeCl_3}{1 \ mol \ FeCl_3}

Multiply by the given number of grams, 345.0.

345.0 \ g \ FeCl_3 *\frac{162.19 \ g \ FeCl_3}{1 \ mol \ FeCl_3}

Flip the fraction so the grams of FeCl₃ will cancel.

345.0 \ g \ FeCl_3 *\frac{1 \ mol \ FeCl_3}{162.19 \ g \ FeCl_3}

345.0 *\frac{1 \ mol \ FeCl_3}{162.19 }

\frac{345.0 \ mol \ FeCl_3}{162.19 }

Divide.

2.12713484 \ mol \ FeCl_3

3. Round

The original measurement of grams, 345.0, has 4 significant figures. We must round our answer to 4 sig figs.

For the answer we calculated, that is the thousandth place.

The 1 in the ten thousandth place tells us to leave the 7 in the thousandth place.

\approx 2.127 \ mol \ FeCl_3

There are about <u>2.127 mole</u>s of iron (III) chloride in 345.0 grams.

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