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3 years ago

A golf pro has 2100 J of kinetic energy and swings his driver which weighs .75 kg. What is the speed of his swing?

Chemistry

2 answers:

jeka57 [31]3 years ago

8 0

Answer : The correct answer is 74.83 m/s .

The kinetic energy is energy possessed by any mass which is moving or have some speed . It is product of mass and velocity . It is expressed as :

$KE = \frac{1}{2} * m* v^2$

Where KE = kinetic energy in J or $kg\frac{m^2}{s^2}$ m = mass in Kg v = speed in m/s²

Unit of KE is Joules (J) .

Givne : KE = 2100 J mass = 0.75 kg v = ?

Plugging value in KE formula =>

$2100 J = \frac{1}{2} * 0.75 Kg * v^2$

$2100 J = 0.375 Kg * v^2$

Dividing both side by 0.375 kg =>

$\frac{2100 J}{0.375 Kg} = \frac{0.375 Kg}{0.375 Kg } * v^2$

$v^2 = 5600 \frac{m^2}{s^2}$

$v= 74.83 \frac{m}{s}$

Kazeer [188]3 years ago

7 0

The speed of his swing is 56 m/s

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Q: How many of the molecules shown contain only one covalent bond?

SVETLANKA909090 [29]

Answer:

cl2 - 1 bond

HCl.- 1 bond

N2 - 3 bond

o2 - 2 bond

Cl requires one electron to complete it's octave so it share it's one electron with other chlorine and make a single covalent bond
H has one electron and Cl requires one so both form one single bond
N requires 3 electrons so it form 3 bonds with other N
oxygen requires 2 electrons so it forms 2 bond with other oxygen

5 0

2 years ago

Use the data given below to construct a Born-Haber cycle to determine the heat of formation of KCl. Δ H°(kJ) K(s) → K(g) 89 K(g)

AURORKA [14]

Explanation:

The net equation will be as follows.

$K(s) + Cl_{2}(g) \rightarrow KCl(s)$

So, we are required to find $\Delta H_{formation}$ for this reaction.

Therefore, steps involved for the above process are as follows.

Step 1: Convert K from solid state to gaseous state

$K(s) \rightarrow K(g)$ , $\Delta H_{1}$ = 89 kJ

Step 2: Ionization of gaseous K

$K(g) \rightarrow K^{+}(g) + e^{-}$ , $H_{2}$ = 418 KJ

Step 3: Dissociation of $Cl_{2}$ gas into chlorine atom .

$\frac{1}{2} Cl_{2}(g) \rightarrow Cl(g)$ , $\Delta H_{3} = \frac{244}{2}$ = 122 KJ

Step 4: Iozination of chlorine atom.

$Cl(g) + e^{-} \rightarro Cl^{-}(g)$ , $H_{4}$ = -349 KJ

Step 5: Add $K^{+}$ ion and $Cl^{-}$ ion formed above to get KCl .

$K^{+}(g) + Cl^{-}(g) \rightarrow KCl(s)$ , $H_{5}$ = -717 KJ

Now, using Born-Haber cycle, value of enthalpy of the formation is calculated as follows.

$\Delta H_{f} = \DeltaH_{1} + \Delta H_{2} + \Delta H_{3} + \Delta H_{4} + \Delta H_{5}$

= 89 + 418 + 122 - 349 - 717

= - 437 KJ/mol

Thus, we can conclude that the heat of formation of KCl is - 437 KJ/mol.

5 0

4 years ago

7. An example of a compound is _____. a) chicken noodle soup b) powerade c) air inside a balloon d) lead pipe e) baking soda (Na

alexira [117]

Answer:

Explanation:

A. Is wrong

To prepare chicken noodle soup, several things are needed to be mixed. This is what makes it a mixture

B is wrong

Powerade is not a compound.

C is wrong

The air inside a balloon is usually helium which is an element and not a compound

D. Lead pipe is not a compound

E. Baking soda is a compound as it contains elements in different ratios

3 0

3 years ago

Read 2 more answers

When two monosaccharides condense to form a disaccharide, what is the other product of the reaction? enter the molecular formula

koban [17]

When two monosaccharides combine to make a disaccharide, water is the byproduct.

<h3>What are monosaccharides ?</h3>

The most fundamental building blocks from which all carbohydrates are constructed are monosaccharides, commonly known as simple sugars. They are the most basic types of sugar. They are typically crystalline solids, colorless, and soluble in water.

These three monosaccharides—glucose, fructose, and galactose—are crucial for nutrition. Six carbon atoms, twelve hydrogen atoms, and six oxygen atoms make up each single sugar molecule.

To learn more about monosaccharides from the given link:

brainly.com/question/13416862

#SPJ4

4 0

1 year ago

During your reaction, you added 0.3 mL concentrated H2SO4 (18.4 M) as the catalyst. At the end of the reaction, you need to add

sattari [20]

Answer:

58.72 mL

Explanation:

The chemical equation for the neutralization reaction is :

H₂SO₄(aq) + Na₂CO₃(s) --------------> Na₂SO₄(aq) + H₂O(l) + CO₂(g)

where;

M₁ = Molarity of H₂SO₄

M₂= Molarity of Na₂CO₃

V₁= Volume of H₂SO₄

V₂ = Volume of Na₂CO₃

Given that :

M₁ = 18.4 M

V₁= 0.3 mL

10% Na₂CO₃ means 100 g of solution contain 10 g of Na₂CO₃

i.e. 10 g Na₂CO₃ dissolved and diluted to 100 mL water.

Molar mass of Na₂CO₃ = 106 g/mol

106 g Na₂CO₃ dissolved in 100 mL will give 0.1 M Na₂CO₃ solution.

However;

If, 106 g Na₂CO₃ ≡ 0.1 M Na₂CO₃

Then, 10 g Na₂CO₃ ≡ 'A' M of Na₂CO₃

By cross multiplying; we have:

106 × A = 10 × 0.1

106 × A = 1

A = (1/106) M/100 mL

A = 10 x (1/106)) M/L

A = (10/106) M

A = 0.094 M

Therefore,the molarity of 10% Na₂CO₃ solution is 0.094 M.

For the Neutralization equation, we have:

M₁V₁ = M₂V₂

18.4×0.3 = 0.094×V₂

Making V₂ the subject of the formula;we have:

$V_2 = \frac{18.4*0.3}{0.094}$

V₂ = 58.72 mL

4 0

3 years ago