Answer:
1. Lactose with C. β-D-galactopyranosyl (1-4) β-D-glucopyranose
2. Maltose with B. α-D-glucopyranosyl (1-4) α-D-glucopyranose
3. Sucrose with A. α-D-glucopyranosyl(1-2) β-D-fructofuranoside
4. Cellobiose with D. β-D-glucopyranosyl(1-4) β-D-glucopyranose
Explanation:
Lactose is made of β-D-glucose and β-D-galactose linked via 1→4 glycosidic linkage
Maltose is made of two α-D-glucose molecule linked via 1→4 glycosidic linkage
Sucrose is made of α-D-glucose and β-D-fructose linked via 1→2 glycosidic linkage
Cellobiose is made of two molecule of β-D-glucose linked via 1→4 glycosidic linkage
Answer:
If a coil of wire is placed in a changing magnetic field, a current will be induced in the wire. This current flows because something is producing an electric field that forces the charges around the wire. (It cannot be the magnetic force since the charges are not initially moving).
Explanation:
Odorants such as Citronellal, Linalool, Nerolidol
Answer:
1200 mL
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Initial volume (V1) = 400 mL.
Initial pressure (P1) = 600 mmHg.
Final volume (V2) =..?
Final pressure (P2) = 200 mmHg
Step 2:
Determination of the final volume i.e the new volume of the gas.
Considering the question given, we understood that the temperature is constant. Therefore the gas is obeying Boyle's law. Using the Boyle's law equation, the new volume is obtained as follow:
P1V1 = P2V2
600 x 400 = 200 x V2
Divide both side by 200
V2 = (600 x 400) /200
V2 = 1200 mL
Therefore, the new volume of the gas is 1200 mL.
<span>A chemist adds 155.0ml of a 4.10 X 10^-5 mmol/L of a zinc oxalate (ZnC2O4)solution to a reaction flask. Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask.
1mmol = 10^-3 mol
Therefore 4.10*10^-5mmol = 4.10*10^-8mol
molar mass ZnC2O4 = 65.39+(2*12.011)+(4*15.99) = 153.372g/mol
You have 4.10*10^-8 mol/litre =153.372 * 4.10*10^-8 = 6.29*10^-6 grams / litre (* see below)
But you have 155ml. Mass of ZnC2O4 = 155/1000*6.29*10^-6 g
Mass is = 9.75*10^-7 grams
1µg = 10^-6 g
You then have 9.75*10^-7/10^-6 = 0.975µg ZnC2O4
(*see below) at this point you could have said:
1µg = 10^-6 g therefore you have a solution of 6.29µg per litre,
155ml = 6.29*155/1000 = 0.975µg ZnC2O4</span>