Answer:
i need a picture or more info to understand
Answer:The answer is C) The total mass of C and D only.
Despite its appearance, air has a ‘thickness’ so when the sun is high in the sky the light travels through the air on a very much shorter path than when it is low on the horizon.
Imagine that air water and you are below the surface, the light from an overhead sun will be quite sharp and bright, but if lower in the sky it will have to travel through much more water to reach you, so will look less bright and sharp. It ma not seem the same, but the atmosphere is just like very thin water, and a low lying sun will be drastically reduced in strength, so all you will see is a sun with a shift to the red end of the spectrum as all the actinic part will be filtered away by that thicker atmosphere.
Answer: 237 ml of stock solution is taken in a 500 ml volumetric flask and diluted with water until the 500 ml mark to obtain 5.5 M diluted solution
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
According to the neutralization law,
where,
= molarity of stock 
solution = 11.6 M
= volume of stock solution = ?
= molarity of dilute solution = 5.5 M
= volume of dilute solution = 500 ml
Thus 237 ml of stock solution is taken in a 500 ml volumetric flask and diluted with water until the 500 ml mark to obtain 5.5 M diluted solution
Answer:
compound 1 = 0.749gF / 1.0gl
compound 2 = 0.4489gF / 1.0gl
compound 3 = 1.047gF / 1.0gl
Explanation:
Given that;
compound mass of iodine in grams mass of fluorine in grams
1 4.75 3.56
2 7.64 3.43
3 9.41 9.86
a) Calculate the mass of fluorine per gram of iodine in each compound:
- compound 1
mass of Fluorine = (3.56gF / 4.75gF) * 1.0gl
= 0.749gF
Now RATIO = 0.749gF / 1.0gl
- compound 2
mass of Fluorine = (3.43gF / 7.64gF) * 1.0gl
= 0.4489gF
Now RATIO = 0.4489gF / 1.0gl
- compound 3
mass of Fluorine = (9.86gF / 9.41gF) * 1.0gl
= 1.047gF
Now RATIO = 1.047gF / 1.0gl
