A red car and a blue car collide. What would be an example of Locard's exchange principle in this situation?

maw [93]

The answer is 297.14 g/mol

6 0

3 years ago

Automobile catalytic Converters use a platinum callus to reduce air pollution by changing emissions such as carbon monoxide CO2

natka813 [3]

Answer:

14 mol O₂

Explanation:

The reaction between CO and O₂ is the following:

CO + O₂ → CO₂

We balance the equation with a coefficient 2 in CO and CO₂ to obtain the same number of O atoms:

2CO + O₂ → 2CO₂

As we can see from the balanced equation, 1 mol of O₂ is required to react with 2 moles of CO. Thus, the conversion factor is 1 mol of O₂/2 mol CO. We multiply the moles of CO by the conversion factor to calculate the moles of O₂ that are required:

28 mol CO x 1 mol of O₂/2 mol CO = 14 mol O₂

6 0

2 years ago

Microscale glassware kits include connectors to fit the smaller glassware. The black connectors should be used when _________ ar

spayn [35]

Answer:

high boiling aromatics

with the same ground glass joint.

Explanation:

The black connectors are more resistant to the reactant than the white connectors. This implies that the black connectors should be used when high boiling aromatics are present, Else, the tan connections can be used.

Thus, the connectors can combine different pieces of glassware or components with the same ground glass joint.

6 0

3 years ago

Name the following ionic compounds: (a) K2Cr2O7, (b) Li2C2O4, (c) CuNO3.

Elis [28]

Answer :

(a) The name of $K_2Cr_2O_7$ is, potassium dichromate.

(b) The name of $Li_2C_2O_4$ is, lithium oxalate.

(c) The name of $CuNO_3$ is, copper nitrate.

Explanation:

Ionic compound : It is a type of compound that is made up of the ions of the two different elements in which one element is a metal and another element is a non-metal.

(a) $K_2Cr_2O_7$

The given compound $K_2Cr_2O_7$ is an ionic compound. It is made up of two different ions which are potassium ion $(K^+)$ and dichromate ion $(Cr_2O_7^{2-})$ .

So, the name of $K_2Cr_2O_7$ is, potassium dichromate.

(b) $Li_2C_2O_4$

The given compound $Li_2C_2O_4$ is an ionic compound. It is made up of two different ions which are lithium ion $(Li^+)$ and oxalate ion $(C_2O_4^{2-})$ .

So, the name of $Li_2C_2O_4$ is, lithium oxalate.

(c) $CuNO_3$

The given compound $CuNO_3$ is an ionic compound. It is made up of two different ions which are copper ion $(Cu^+)$ and nitrate ion $(NO_3^{-})$ .

So, the name of $CuNO_3$ is, copper nitrate.

4 0

3 years ago

A solution is prepared from 4.5701 g of magnesium chloride and 43.238 g of water. The vapor pressure of water above this solutio

balandron [24]

Answer:

i = 2.483

Explanation:

The vapour pressure lowering formula is:

Pₐ = Xₐ×P⁰ₐ (1)

For electrolytes:

Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ

Where:

Pₐ is vapor pressure of solution (0.3624atm), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (0.3804atm)

4.5701g of MgCl₂ are:

4.5701g ₓ (1mol / 95.211g) = 0.048000 moles

43.238g of water are:

43.238g ₓ (1mol / 18.015g) = 2.400 moles

Replacing in (1):

0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm

0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)

2.4mol + i*0.048mol = 2.4mol / 0.9527

2.4mol + i*0.048mol = 2.5192mol

i*0.048mol = 2.5192mol - 2.4mol

i = 0.1192mol / 0.048mol

i = 2.483

I hope it helps!

4 0

3 years ago