Question

A 8.01-nC charge is located 1.87 m from a 4.50-nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other.(b) Is the force attractive or repulsive?

Answer 1

Answer:

Explanation:

Given

$q_1=8.01\ nC$

$q_2=4.50\ nC$

distance between the charges is given by $d=1.87\ m$

Electrostatic force between the charges is given by

$F_{12}=F_{21}=\frac{kq_1q_2}{d^2}$

where k=constant $=9\times 10^{9}$

$F_{12}=F_{21}=\frac{9\times 10^9\times 8.01\times 4.50\times 10^{-18}}{(1.87)^2}$

$F_{12}=F_{21}=92.769\times 10^{-9}\ N$

as both the charges are of similar nature therefore they repel each other