Answer:
False
Explanation:
A double covalent bond means 2 atoms or elements are sharing <u>4</u><u> </u><u>e</u><u>l</u><u>e</u><u>c</u><u>t</u><u>r</u><u>o</u><u>n</u><u>s</u>.
*single covalent bond shares 2 electrons.
Answer:
Energy is transferred from one object to another when a reaction takes place.
Explanation:
Energy comes in many forms and can be transferred from one object to another as heat, light, or motion, to name a few.
The answer could be It is a well known fact that energy can neither be created and nor be destroyed but can be transformed from one form to another.
Now talking about your example in a typical light bulb electrical energy is converted into light energy and heat energy. Now when the electric current flows through the conductor/filament in the light bulb,this would cause vibrations and the free ions are more likely to go to an higher energy level,and when the ions come back to their original state,the difference in the two energy levels is usually emitted as a photon,thus light energy is obtained and the heat energy is the energy dissipated as a result of flow of electricity through the conductor.
Anything that gets transformed into light energy or in better words ElectroMagnetic Energy would be a result of this.
Info: NACl2<span> might be an improperly capitalized: </span>NaCl2<span>. Balanced equation: NA + Cl2 = </span>NACl<span>2. </span>Reaction type<span>: synthesis. Please tell about this free chemistry ...</span>
Answer:
last choice
Explanation:
Specific heat of a metal is j/kg-c
It says nothing about melting point or heat of fusion
A = twice B = 2 * j/kg-c B = j/kg-c
if j is constant and mass is the same we can write this more like
A = 2 /C and B = 1/C
or A ~ C/2 and B~ C
now you can see that the temp change in A will be 1/2 that of B
Answer:
The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.
Explanation:
Using Boyle's law
Given ,
V₁ = 3.6 L
V₂ = ?
P₁ = 1.0 atm
P₂ = 13.3 atm
Using above equation as:
<u>The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.</u>
