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Virty [35]
3 years ago
12

An aqueous solution of iron(II) sulfate (FeSO4) is prepared by dissolving 2.00 g in sufficient deionized water to form a 200.00

mL solution. Calculate the molarity of the solution.
Chemistry
1 answer:
ElenaW [278]3 years ago
3 0

Answer:

0.066mol/dm^3

Explanation:

The molarity is simply calculating the number of moles in 1L or 1000ml

To get this, we need to know the amount in grammes that would be present in 1L.

Since 2g is sufficient for 200ml, then for 1000ml, the amount sufficient would be 5 * 2 = 10g

Now to get the number of moles needed, we need to know the molar mass of the compound. That is molar mass of FeSO4 = 56 + 32 + 4(16) = 152g/mol

The number of moles is thus 10/152 = 0.066 mol/dm^3

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This is because amino group of p-aminobenzoic acid is an aniline and is less electrophilic than an alkyl amine.

<h3>What is an Aniline?</h3>

This is an aromatic amine which consists of a phenyl group attached to an amino group.

The amino group of p-aminobenzoic acid being an aniline makes it less electrophilic which is why an alkyl amine participates in the reaction instead.

Read more about Aniline here brainly.com/question/9982058

5 0
2 years ago
Explain how the mass of a single atom in an element (in amu), the mass of one mole of that element, and Avogadro’s number are re
Eva8 [605]

Answer: For 1 mole of a single atom it is equal to its molar mass. And a single atom, 1 mole is equal to the Avogadro's Number.

Explanation: The relationship can be expressed through the following:

1 mole = molar mass of an atom/ compound

1 atom x 1 mole / 6.022x10^23  atoms

4 0
3 years ago
Which of the following is TRUE?Which of the following is TRUE?A basic solution does not contain H3O+An neutral solution does not
schepotkina [342]

Answer:

b

Explanation:

b

5 0
3 years ago
Two unknown compounds are tested. Compound 1 contains 15.0g of hydrogen and 120.0g of oxygen. Compound 2 contains 2.0g of hydrog
ivann1987 [24]

Answer:

The both compounds are different.

Explanation:

In order to confirm weather both compounds are same we will check the mole ration. If it is same the compounds will be same.

Given data:

For compound 1.

Mass of hydrogen = 15 g

Mass of oxygen = 120 g

Moles of hydrogen and oxygen = ?

Number of moles of hydrogen = 15 g/ 1g/mol = 15 mol

Number of moles of oxygen = 120 g/ 16 g/mol = 7.5 mol

Total number of moles = 22.5 mol

% of hydrogen = 15 /22.5 × 100 = 66.7%

% of oxygen = 7.5 / 22.5× 100 = 33.3%

For compound 2:

Mass of hydrogen = 2 g

Mass of oxygen = 32 g

Moles of hydrogen and oxygen = ?

Number of moles of hydrogen = 2 g/ 1g/mol = 2 mol

Number of moles of oxygen = 32 g/ 16 g/mol = 2 mol

Total number of moles = 4 mol

% of hydrogen = 2 /4 × 100 = 50%

% of oxygen = 2 / 4× 100 = 50%

7 0
3 years ago
8. __H2 + __O2-&gt; __H2O
Rus_ich [418]

Anser:

Explanation:

hope this helps

8 0
2 years ago
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