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Virty [35]
3 years ago
12

An aqueous solution of iron(II) sulfate (FeSO4) is prepared by dissolving 2.00 g in sufficient deionized water to form a 200.00

mL solution. Calculate the molarity of the solution.
Chemistry
1 answer:
ElenaW [278]3 years ago
3 0

Answer:

0.066mol/dm^3

Explanation:

The molarity is simply calculating the number of moles in 1L or 1000ml

To get this, we need to know the amount in grammes that would be present in 1L.

Since 2g is sufficient for 200ml, then for 1000ml, the amount sufficient would be 5 * 2 = 10g

Now to get the number of moles needed, we need to know the molar mass of the compound. That is molar mass of FeSO4 = 56 + 32 + 4(16) = 152g/mol

The number of moles is thus 10/152 = 0.066 mol/dm^3

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3 years ago
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A solution of 0.2 M Sulfuric acid is titrated with a 0.2 M basic solution. In three to five sentences, explain how you can use t
SCORPION-xisa [38]

If there are 0.2 M solutions of both acid and base, the concentrations of hydrogen and hydroxide ions will be equal at equivalence point.

The reaction of sulfuric acid and a basic solution BOH occurs as follows;

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5 0
3 years ago
How many moles of hcl are present in 40.0 ml of a 0.035 m solution?
Elden [556K]

Answer:

0.0014 moles is present in 40cm³ of 0.035M of HCl solution

Explanation:

Molarity = 0.035M

V = 40.0mL

1mL = 1cm³

V = 40cm³

0.035 moles = 1000cm³

X moles is present in 40cm³

X = (40 * 0.035) / 1000

X = 0.0014moles

0.0014 moles is present in 40cm³ of solution

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