Answer:
I’m trying to do something similar to that
Explanation:
Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
Answer:
11.3 g.
Explanation:
Hello there!
In this case, since the combustion of butane is:
Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:
Therefore, the resulting mass of water is:
Best regards!
The answer to your question is
D: Unshared Pair
Hope this helps you :))))
In order from most to least similar:
1. Germanium
2. Lead
3. Phosphorus
4. Chlorine
The elements in the same column as the element you have are the most similar. The rows are not. For example, though chlorine and magnesium are in the same row, they have very different properties, whereas chlorine and fluorine more similar
