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alekssr [168]
3 years ago
13

A sealed can of your favorite soda has a carbon dioxide gas (C0) volume of 0.05 L. When it is refrigerated, the

Chemistry
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

<h2>0.102 L</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{207000 \times 0.05}{101000}  =  \frac{10350}{101000}  \\  = 0.102475...

We have the final answer as

<h3>0.102 L</h3>

Hope this helps you

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Answer:

The amount of sucrose that must be added is 1.66 moles

Explanation:

Colligative property of lowering vapor pressure has this formula:

Vapor pressure of pure solvent (P°) - Vapor pressure of solution = P° . Xm

We have both vapor pressure (pure solvent and solution9, so let's determine the ΔP

ΔP = 92.6 Torr - 72 Torr = 20.6 Torr

Let's add the data in the formula

20.6 Torr = 92.6 Torr . Xm

Xm = Mole fraction of solute → (mol of solute/ mol of solute + mol of solvent)

Mol of solvent = 5.83 mol (data from the problem)

Therefore Xm = 20.6 Torr / 92.6 Torr → 0.222

Let's find out the moles of solute (our unknown value)

0.22 = moles of solute / moles of solute + 5.83 moles of solvent

0.222 (moles of solute + 5.83 moles of solvent) = moles of solute

0.222 moles of solute + 1.29 moles of solvent = moles of solute

1.29 moles of solvent = moles of solute - 0.222 moles of solute

1.29 moles = 0.778 moles of solute

1.29 / 0.778 = moles of solute → 1.66 moles

3 0
3 years ago
How many moles of hydrochloric acid are required to produce .40 moles of hydrogen gas?
mash [69]

Answer:

0.80 Moles of Hydrochloric Acid would be required to produce 0.40 Moles of hydrogen gas due to the equation ratios

Explanation:

How many moles of hydrochloric acid are required to produce .40 moles of hydrogen gas?

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Hydrogen gas = H2

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Cl = 1-

HCL = H2 + Cl2

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First convert volume to mass:

mass = 0.789 g/mL * 155 mL = 122.295 g

 

Then convert mass to number of moles:

number of moles = 122.295 g * (1 mole / 46 g) = 2.66 moles

 

Using avogadros number, we get the molecules:

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