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Alika [10]
3 years ago
10

The question is attached to this.

Physics
1 answer:
Rzqust [24]3 years ago
3 0

Answer:

B

Explanation:

Increase in the rate or speed of something

the rate of change of velocity per unit of time.

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At t1 = 1.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is At t2 = 2.00 s (l
Marta_Voda [28]

Answer:

2.925 meters

Explanation:

See the remaining part of required information in the attached image

Solution

The formula for calculating velocity is equal to

v = \frac{r\theta}{t_2 - t_1}

Where v is the velocity, t_1, t_2,\theta are time range for two acceleration vectors and angle between two acceleration vector respectively and r is the radius of the circle

Putting the give values in above equation we get

v = \frac{r * \frac{\pi }{2} }{2 -1} \\v = \frac{r\pi }{2}

Acceleration is equal to

\sqrt{6^2 + 4^2} \\\sqrt{36+16} \\\sqrt{52} \\= 7.21

Radius is equal to

\frac{v^2}{a}

Putting the given values we get -

r = \frac{(\frac{r\pi }{2})^2}{7.211} \\r = \frac{4 * 7.211 }{\pi^2 } \\r = 2.925

3 0
4 years ago
Temporary magnets are made up of _______.​
Cloud [144]

Answer:

Temporary magnets are made from soft metals,

Explanation:

they only retain their magnetism while near a permanent magnetic field or electronic current. Common temporary magnets include nails and paperclips, which can be picked up or moved by a strong magnet.

3 0
3 years ago
Read 2 more answers
What is an static electricity
Ipatiy [6.2K]

Answer:

d

Explanation:

5 0
4 years ago
The distance from the earth to a star that has identical apparent and absolute magnitudes is ____ .
PSYCHO15rus [73]
I think it's distance.
5 0
4 years ago
А masd<br>Of 500kg a raised to a height of 6m In 30s<br>Find (a) Workdone .​
Mazyrski [523]

Answer:

Work done is 882000joule.

power is 29400watt.

Explanation:

given,

Mass(m)=500kg

Acceleration due to gravity(g)=9.8m/s²

Height(h)=6m

Time taken(t)=30s

Workdone=?

Power=?

now,

workdone=force*displaxement

= m*g*h

=500*9.8*6

=8,82,000joule

so, the work done by the man is 8,82,000joule.

then,

power=workdone/time taken

=8,82,000/30

=29,400watt

so, the required power to lift a load is 29,400watt.

5 0
3 years ago
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