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shepuryov [24]
3 years ago
8

An object is located 40.0 cm from a convex lens. The lens focuses light at a

Physics
1 answer:
lana66690 [7]3 years ago
5 0

The image of distance (di) of the object is 13.33 cm.

<u>Explanation:</u>

Given data in the problem,

The object located at a distance from the convex lens.

do = 40.0 cm

The distance at which the light is focused.

f= 10.0 cm.

We need to find the image of distance di.

The lens equation gives the quantitative relation among the image distance (di), the object distance (do), and the focal length (f).

The equation is given by,

\frac{1}{f} =\frac{1}{di} +\frac{1}{do}.

\frac{1}{10} =\frac{1}{di} +\frac{1}{40}.

\frac{1}{10} -\frac{1}{40} =\frac{1}{di}.

\frac{4-1}{40}=\frac{1}{di}.\\

\frac{3}{40} = \frac{1}{di}.

3 di=40.

di=\frac{40}{3}.

di = 13.33 cm

The image of distance (di) of the object is 13.33 cm.

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The question is incomplete. The complete question is :

A viscoelastic polymer that can be assumed to obey the Boltzmann superposition principle is subjected to the following deformation cycle. At a time, t = 0, a tensile stress of 20 MPa is applied instantaneously and maintained for 100 s. The stress is then removed at a rate of 0.2 MPa s−1 until the polymer is unloaded. If the creep compliance of the material is given by:

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